Answer:
the rate of the change of the length of the shadow is - 0.8625 m/s.
The negative(-) sign means the length of the shadow decreases at a rate of 0.8625 m/s.
Explanation:
Given the data in the question;
Let x represent the man's distance from building,
initially x = 1m2
dx/d t= -2.3 m/s
Also Let y represent shadow height
so we determine dy/dt when x is 4m from the building
form the image description of the problem, we see two-like triangles with the same base and height ratios
so
2 / (12-x) = y / 12
24 = y(12 - x )
y = 24 / (12-x)
dy/dt = 24/(12-x)² × dx/dt
Now at x = 4,
we substitute
dy/dt will be;
⇒ 24/(12 - 4)² × -2.3
= 24/64 - 2.3
= 0.375 × -2.3
dy/dt = - 0.8625 m/s
Therefore, the rate of the change of the length of the shadow is - 0.8625 m/s.
The negative(-) sign means the length of the shadow decreases at a rate of 0.8625 m/s.
Rocks and sediments I believe
1200 mL
1.2L*1000mL/1L=1200mL (after canceling alike units)
Hope this helps:)
Answer:
Vf = 4.77 m/s
Explanation:
During the downward motion we can easily find the final velocity or the velocity with which the ball hits the ground, by using third equation of motion. The third equation of motion is given as follows:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = height = 1.16 m
Vf = Final Velocity of Ball = ?
Vi = Initial Velocity of Ball = 0 m/s (Since, ball was initially at rest)
Therefore, using these values in the equation, we get:
(2)(9.8 m/s²)(1.16 m) = Vf² - (0 m/s)²
Vf = √(22.736 m²/s²)
<u>Vf = 4.77 m/s</u>