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oksano4ka [1.4K]
3 years ago
11

What is the final concentration of DD at equilibrium if the initial concentrations are [A][A]A_i = 1.00 MM and [B][B]B_i = 2.00

MM ? Express your answer to two significant figures and include the appropriate units.

Physics
1 answer:
pentagon [3]3 years ago
8 0

Answer:

A) Concentration of A left at equilibrium of we started the reaction with [A] = 2.00 M and [B] = 2.00 M is 0.55 M.

B) Final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M is 0.90 M.

[D] = 0.90 M

Explanation:

With the first assumption that the volume of reacting mixture doesn't change throughout the reaction.

This allows us to use concentration in mol/L interchangeably with number of moles in stoichiometric calculations.

- The first attached image contains the correct question.

- The solution to part A is presented in the second attached image.

- The solution to part B is presented in the third attached image.

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I drop a meter stick , and catch it as it falls. If it fell exactly 22 cm, how much did it take me to catch the meter stick (wha
statuscvo [17]
D=Vot+1/2at^2

In this case, there is no initial y velocity so the term Vot=0 so d=1/2at^2

acceleration=acceleration due to gravity=-9.8m/s^2

It falls - 22cm or -0.22m

We have - 0.22=1/2(-9.8)t^2

t^2=(-0.44)/(-9.8)

t=sqrt[0.44/9.8]
3 0
3 years ago
A cell membrane consists of an inner and outer wall separated by a distance of approximately 10nm. Assume that the walls act lik
Lady bird [3.3K]

Answer:

The options are approximations of the exact answers:

A) 1\times10^6N/C

B) 2\times10^{-13}N

C) 1\times10^{-2}V

D) Toward the inner wall

E) 3\times10^{-17}J

Explanation:

A) The electric field in a parallel plate capacitor is given by the formula E=\frac{\sigma}{k\epsilon_0}, where \epsilon_0=8.85\times10^{-12}C/Vm and in our case \sigma=10^5C/m^2 and, for air,k=1.00059, so we have:

E=\frac{10^5C/m^2}{(1.00059)(8.85\times10^{-12}C/Vm)}=1.13\times10^6N/C

B) The K+ ion has one elemental charge excess, so its charge is q=1.6\times10^{-19}C, and the force a charge experiments under an electric field E is given by F=qE, so we have:

F=(1.6\times10^{-19}C)(1.13\times10^6N/C)=1.81\times10^{-13}N

C) The potential difference between two points separated a distance d under an uniform electric potential E is given by \Delta V=dE, so we have:

\Delta V=(10\times10^{-9}m)(1.13\times10^6N/C)=1.13\times10^{-2}V

D) The electic field goes from positive to negative charges, so it goes towards the inner wall.

E) The work done by an electric field through a potential difference \Delta V on a charge Q is W=Q\Delta V, and is equal to the kinetic energy imparted on it, so we have:

K=(3\times10^{-15}C)(1.13\times10^{-2}V)=3.39\times10^{-17}J

5 0
4 years ago
Which class of organic molecules includes those whose main purpose is long-term energy storage?
omeli [17]

Answer:

Fats.

Explanation:

A fat molecule which is called a Triglyceride consists of two main components which are glycerol and 3 fatty acids. Fats are solids and oils are liquids at room temperature. They also include saturated and unsaturated fats.

Cells store energy for long-term use in the form of lipids called fats which provides insulation from the environment for plants and animals.

3 0
3 years ago
ANSWER = BRAINLIEST<br><br>PLEAASSEE
baherus [9]

1) Mass won't change (59 kg).

2) W_{TM}=mg_{_{TM}}\medskip\\m=\dfrac{W_{TM}}{g_{_{TM}}}\medskip\\W_{E}=mg_{_E}=W_{TM}\dfrac{g_{_E}}{g_{_{TM}}}=20\times \dfrac{9.08}{1.62}\approx 112.0988

3) W_{TM}=mg_{_{TM}}=100\times 1.62=162

4) mg_{_{object}}=G\dfrac{M_{object}m}{r^2}\medskip\\g_{_{object}}=G\dfrac{M_{object}}{r^2}

As G and r are constants, g_{_{object}}\propto M_{object}. In other words, the more massive the object is, the bigger its gravitational acceleration (obviously, the lighter the object is, the lesser its gravitational acceleration)

5 0
3 years ago
Read 2 more answers
The value of g at the height of the space shuttle’s orbit is
grin007 [14]

Answer:

g'=9.3345\ m.s^{-2}

Explanation:

The minimum height of a space shuttle from the surface of the earth is 304 kilometers.

So according to this data we calculate the value to g at that height.

We have the formula:

g'=g(1-\frac{2h}{R} )

where:

g' = the acceleration due to gravity at the given height 'h' above the earth

R = radius of the earth

g = the acceleration due to gravity at the surface of the earth

Now, using eq. (1)

g'=9.8(1-\frac{304\times 10^3}{64000\times 10^3} )

g'=9.3345\ m.s^{-2}

3 0
4 years ago
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