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Irina18 [472]
2 years ago
11

PLEASE ANSWER THE SCREENSHOT ASAP.

Mathematics
1 answer:
blondinia [14]2 years ago
6 0

Answer:

2.7 ounce

Step-by-step explanation:

so first we need to convert the improper fractions into a whole fraction:

7\frac{5}{12} = 89/12

4\frac{5}{7} = 33/7

then you find out:

89/12 = 7.4

33/7 = 4.7

∴7.4-4.7 = 2.7 ounce

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A bag contain 5 red marbles,4 green marbles and 1 blue marble. A marble is chosen at random from the bag and not replaced; then
jarptica [38.1K]

Answer:

\frac{2}{15}

Step-by-step explanation:

GIVEN: A bag contain 5 red marbles,4 green marbles and 1 blue marble. A marble is chosen at random from the bag and not replaced, then a second marble is chose.

TO FIND: What is the probability both marbles are green.

SOLUTION:

Total marbles in bag =10

total number of green marbles =4

Probability that first marble will be green P(A)=\frac{\text{total green marbles}}{\text{total marbles}}

                                                                    =\frac{4}{10}=\frac{2}{5}

Probability that second marble will be green P(B)=\frac{\text{total green marble in bag}}{\text{total marble in bag}}

                                                                                    \frac{3}{9}=\frac{1}{3}

As both events are disjoint

probability both marbles are green =P(A)\times P(B)

                                                           =\frac{2}{5}\times\frac{1}{3}=\frac{2}{15}

Hence  the probability both marbles are green is \frac{2}{15}

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What is the graph of the function f(x) = the quantity of x plus 2, all over x minus 3
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Answer:


Step-by-step explanation:

The given function is f(x)=\frac{x+2}{x-3} and we need to graph it.

In order to graph this function, we'll find below things:

Horizontal asymptote:

Since the degree of both numerator and denominator is same. Hence, the horizontal asymptote is the ratio of leading coefficient of numerator to the leading coefficient of  denominator.

Horizontal  asymptote is y = 1/1 = 1

Vertical asymptote:

Vertical asymptote occurs where the denominator is zero.

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Using these, we can draw the graph of the rational expression.


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