<h3><u>Answer;</u></h3>
<u>= 128.772 g of water</u>
2C6H14 + 13 O2 → 6CO2 + 14 H2O
<h3><u>Explanation</u>;</h3>
1 mole of Hexane contains 86 g
Therefore;
87.91 grams of hexane will contain
= 87.91 g/86 g
= 1.022 moles
The balanced reaction for the combustion of Hexane is given by
2C6H14 + 13 O2 → 6CO2 + 14 H2O
Therefore; the mole ratio of C6H14 :H2O is
= 2 : 14
= 1: 7
therefore moles of water from 1.022 moles of Hexane will be;
= 1.022 ×7
= 7.154 moles
Mass of water will be;
= 7.154 moles× 18
<u>= 128.772 g of water</u>
Answer:
1,6,8
Explanation:
Periodic Table- H=1.C=6,O=8
Hydrogen is H, Carbon is C, Oxygen is O
A conductor of electricity
The required mass of calcium bromide is 35.98 grams.
<h3>What is molarity?</h3>
Molarity is any solution is define as the number of moles of solute present in per liter of solution as;
M = n/V, where
- M = molarity = 4M
- V = volume = 45mL = 0.045L
Moles will be calculated by using the above equation as:
n = (4)(0.045) = 0.18 mole
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
- W = given mass
- M = molar mass
Mass of CaBr₂ = (0.18mol)(199.89g/mol) = 35.98g
Hence required mass of CaBr₂ is 35.98 grams.
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