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Anna71 [15]
3 years ago
7

Identify an element when supplied with the natural abundance and mass of each isotope

Chemistry
1 answer:
lozanna [386]3 years ago
4 0

The element can also be called gold-197. It has Mass number is 197, atomic number is 79 and electrons 79, Atoms that have the same number of protons but different number of neutrons. Isotopes have identical numbers of protons and electrons.

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About how many elements are found on the periodic table? Question 8 options:
krek1111 [17]

the answer is actually 118 look it up

3 0
3 years ago
A basketball weighs approximately 1.35 kg. What is this mass in grams (g)?<br><br> step by step
choli [55]

Answer:

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8 0
3 years ago
Thallium-207 decays exponentially with a half life of 4.5 minutes. if the initial amount of the isotope was 28 grams, how many g
Agata [3.3K]
An exponential decay law has the general form: A = Ao * e ^ (-kt) =>

A/Ao = e^(-kt)

Half-life time => A/Ao = 1/2, and t = 4.5 min

=> 1/2 = e^(-k*4.5) => ln(2) = 4.5k => k = ln(2) / 4.5 ≈ 0.154

Now replace the value of k, Ao = 28g  and t = 7 min to find how many grams of Thalium-207 will remain:

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Answer 9.5 g.
7 0
4 years ago
A chemical might be used to melt ice if it raises the temperature of the ice. This best type reaction to accomplish this would b
Setler79 [48]
<h2>Answer:</h2>

B) endothermic reaction.

<h2>Explanation:</h2>

Melting of ice is endothermic because it is taking heat from the environment, feeling cold, because it requires energy to break the ice bonds. It's also why you feel cold when wet it takes energy to evaporate water. The ice absorbs the energy from the environment. Its internal potential energy increases, therefore, it's endothermic. It also increases the entropy of reaction.

7 0
3 years ago
Determine the molality of an aqueous solution that is 16.5 percent urea by mass
yarga [219]

Take a hypothetical sample of exactly 100 grams of the solution.  

(16g urea) / (60.06 g urea/mol) = 0.2664 mol urea  

((100 g total) - (16g urea)) = 84.0 g H2O = 0.0840 kg H2O  

(0.2664  mol) /0.0840  (kg) = 3.17143mol/kg = 3.18m urea


7 0
3 years ago
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