Question

a slot machine has 3 dials each dial has 40 positions. two of which are "jackpot" To win the jackpot all three dials must be in the jackpot position. Assuming each play spins the dials and stops independently and randomly What are the odds of one player winning the jackpot? A. 0.0125% B. 0.00156%...C. 3.7%.....D. 0.014%​

Answer 1

The odds of one player that wins the jackpot should be 0.00156%.

Given that,

• There are 3 dials.
• In each dial, there are 40 positions.

• So, the probability of receiving the jackpot should be $\frac{1}{40}$

Now the odds of one player that wins the jackpot should be

$= \frac{1}{40} \times \frac{1}{40} \times \frac{1}{40}$

= 0.00156%

Therefore we can conclude that the odds of one player that wins the jackpot should be 0.00156%.

Learn more about the odd here: brainly.com/question/2133449