Answer:
Light refracts whenever it travels at an angle into a substance with a different refractive index (optical density). This change of direction is caused by a change in speed. ... When light enters a more dense substance (higher refractive index), it 'bends' more towards the normal line.
Parks and open spaces
hope that helps if u have any questions let me know and also if u could mark this as brainliest i would really appreciate it!
I think the substance that will heat up faster would be the silver metal since it has a higher heat capacity. Heat capacity is the amount of heat needed to raise the temperature of the system into one degree. Heat capacity and heat energy is directly related so higher value of heat capacity would lead to higher heat energy.
Answer:
0.088 mole of Al.
Explanation:
First, we shall determine the number of mole in 23.6 g of AlBr₃.
This is illustrated below:
Mass of AlBr₃ = 23.6 g
Molar Mass of AlBr₃ = 27 + 3(80) = 267 g/mol
Mole of AlBr₃ =.?
Mole = mass/Molar mass
Mole of AlBr₃ = 23.6 / 267
Mole of AlBr₃ = 0.088 mol
Next, we shall writing the balanced equation for the reaction.
This is given below:
2Al(s) + 3Br₂(l) → 2AlBr₃(s)
From the balanced equation above,
2 moles of Al reacted with 3 mole of Br₂ to 2 moles AlBr₃.
Finally, we shall determine the number of mole of Al needed for the reaction as follow:
From the balanced equation above,
2 moles of Al reacted to 2 moles AlBr₃.
Therefore, 0.088 mole of Al will also react to produce 0.088 mole of AlBr₃.
Answer:
-54 kJ/mol
Explanation:
Given that:
A student mixed 50 ml of 1.0 M HCl and 50 ml of 1.0 M NaOH in a coffee cup calorimeter and calculated the molar enthalpy change of the acid-base neutralization reaction to be –54 kJ/mol
i.e
50 ml of 1.0 M HCl + 50 ml of 1.0 M NaOH -----> -54 kJ/mol
If he repeat the same experiment with :
100 ml of 1.0 M HCl + 100 ml of 1.0 M NaOH. ------> ????
From The experiment; the molar enthalpy of change of the acid-base neutralization reaction will be -54 kJ/mol
This is because : The second reaction requires 50 ml in order to neutralize the reaction, then the remaining 50 ml will be excess, Hence, there is no change in the enthalpy of the reaction.
Similarly; we can assume that :
In the first reaction; P moles of is used to liberate Q kJ heat ; then the change in molar enthalpy will be Q/P (kJ/mol).
SO; when he used 100 ml ;
then the amount of moles used is double, likewise the heat liberated will be doubled ;
So;
2P moles is used to liberate 2Q kJ heat ;
2P/2Q = Q/P ( kJ/mol) = -54 kJ/mol
