Answer:
C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)
Explanation:
Propane can be turned into hydrogen by the two-step reforming process.
In the first step, propane and water react to form carbon monoxide and hydrogen. The balanced chemical equation is:
C₃H₈(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g)
In the second step, carbon monoxide and water react to form hydrogen and carbon dioxide. The balanced chemical equation is:
CO(g) + H₂O(g) ⇒ H₂(g) + CO₂(g)
In order to get the net chemical equation for the overall process, we have to multiply the second step by 3 and add it to the first step. Then, we cancel what is repeated.
C₃H₈(g) + 3 H₂O(g) + 3 CO(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g) + 3 H₂(g) + 3 CO₂(g)
C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)
Answer:
7.53×10²³ molecules
Explanation:
Given data:
Number of moles of carbonic acid = 1.25 mol
Number of molecules of CO₂ produced = ?
Solution:
Chemical equation:
H₂CO₃ → CO₂ + H₂O
Now we will compare the number of moles of carbonic acid with CO₂ from balanced chemical equation.
H₂CO₃ : CO₂
1 : 1
1.25 : 1.25
Number of molecules can be determine by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
Number of molecules:
1 mole = 6.022 × 10²³ molecules
1.25 mol × 6.022 × 10²³ molecules / 1 mol
7.53×10²³ molecules
Answer: 1.79 x 10^-5
Explanation: The equilibrium constant of a reaction can be calculated from the quotient of the concentrations of the products over the concentrations of the reactants, with each termed raised to their respective stoichometric coefficients.
For acetic acid, this equilibrium expression is:
![Kc=\frac{[H+] [CH3COO-]}{[CH3COOH]}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH%2B%5D%20%5BCH3COO-%5D%7D%7B%5BCH3COOH%5D%7D)
Replacing the equilibrium concentrations given by the exercise into the expression above, the equilibrium constant, Kc will be obtained and it is found to be equal to 1.79 x 10^-5.
Well, the molar mass of acetone would be
3(12.011)+6(1.008)+15.999 , which cleans up to be 58.08 grams.
out of this total, 3(12.011), or 36.033 grams are carbon
So, to find the percent, you do part over whole
36.033/58.08, which equals 0.6204 with significant figures
multiply that by 100 to get 62.04%
Hope that helps!
Answer:
Group 1
because they have just one valance electron, group 1 elements are very reactiv.