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IRINA_888 [86]
3 years ago
5

An athlete preparing for a marathon runs 21.3 miles. How many kilometers did they run? (please give fourmula)

Chemistry
1 answer:
MatroZZZ [7]3 years ago
6 0

Answer:

Athlete will run \[34.272Km\]

Explanation:

One mile equals to \[1.609Km\]  

 & \therefore 21.3\text{ mile = 1}\text{.603}\times \text{21}\text{.3}Km \\  & 21.3\text{ mile = 34}\text{.2717}Km \\  

Thus, the athlete will run \[34.2717Km\].

Learn more about unit conversion here:

brainly.com/question/19730577

brainly.com/question/17187413

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A shiny chunk of metal is found to have a mass of 37.28g. The metal is dropped into a graduated cylinder which contains 20.0 mL
Amanda [17]

Answer: The density of the material is 2.66 g/mL and it is likely this  is made of Aluminum

Explanation:

The first step to know the material of the chunk of metal is to calculate its density. The general formula for density is P (density) = \frac{m (mass)}{ v (volume)}. Moreover, in this case, it is known the mass is 37.28 g, but the volume is not directly provided. However, we know the water in the graduated cylinder had a volume of 20.0 mL and this increased to 34.0 mL when the chunk of metal is added, this means the volume of the metal is 14 mL (34.0 mL - 20.0 mL = 14 mL). Now let's calculate the density:

P = \frac{37.28g}{14.0mL}

P = 2.66 g/mL

This means the density of this metal is 2.66 g/mL, which can be rounded as 2. 7 g/mL, and according to the chart, this is the density of aluminum. Therefore, this material of this chunk is aluminum.

6 0
4 years ago
The reaction of Cr2O3 with silicon metal at high temperatures will make chromium metal. 2CrO3(s) + 3Si(s)----&gt; 4Cr(l) + 3SiO2
nalin [4]

Answer: 51.45 grams of excess reagent is left after the completion of reaction.

Explanation: For the calculation of moles, we use the formula:

Moles=\frac{\text{Given mass}}{\text{Molar mass}}     ....(1)

  • For Si

Given mass = 92 grams

Molar mass = 28g/mol

Putting values in equation 1, we get:

Moles=\frac{92g}{28g/mol}=3.285moles

  • For Cr_2O_3

Given mass = 112 grams

Molar mass = 116g/mol

Putting values in equation 1, we get:

Moles=\frac{112g}{116g/mol}=0.965moles

The reaction follows:

2Cr_2O_3(s)+3Si(s)\rightarrow 4Cr(l)+3SiO_2(s)

By Stoichiometry,

2 moles of Cr_2O_3 reacts with 3 moles of silicon

So, 0.965 moles of Cr_2O_3 reacts with = \frac{3}{2}\times 0.965 = 1.4475 moles of Silicon.

As, the moles of silicon is more than the required amount and is present in excess.

So, the excess reagent for the reaction is Silicon.

Moles of silicon remained after reaction = 3.285 - 1.4475 = 1.8375 moles

To calculate the amount of Silicon left in excess is calculated by using equation 1:

1.8375=\frac{\text{Given mass}}{28}

Amount of Silicon in excess will be 51.45 grams.

5 0
4 years ago
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