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3 years ago

5

Solve for x ( I already did 1 and 3 )

1 answer:

dusya [7]3 years ago

4 0

Answer:

Answer for problem two: 2

Answer for problem four: 1/3 (one-third)

Answer for code: FHDA

Step-by-step explanation:

For Two: I had to multiply 4 to both sides which would cross the 4 on the left side out and the right side would become 20. Then, I just subtracted 18 to leave x alone and got x=2.

For Four: I had to subtract one from both sides to make 33x on the left and 11x on the right. 33x=11. Then, I had to do: 11/33 to leave the x alone and I ended up with 1/3.

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Zorah, a musician, pays $120 to have her instrument tuned and $10 per hour for a booth at a fair. She estimates that she earns $

-BARSIC- [3]

Subtracting 10x from the given equation gives
120 = 15x
Then dividing by 15 gives
8 = x

Zorah will have to play 8 hours in order to break even (cover her expenses exactly).

8 0

3 years ago

Read 2 more answers

“encontrar la integral indefinida y verificar el resultado mediante derivación”

Oliga [24]

$I=\displaystyle\int\frac x{(1-x^2)^3}\,\mathrm dx$

Haz la sustitución:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{y^3}=\frac1{4y^2}+C=\frac1{4(1-x^2)^2}+C$

Para confirmar el resultado:

$\dfrac{\mathrm dI}{\mathrm dx}=\dfrac14\left(-\dfrac{2(-2x)}{(1-x^2)^3}\right)=\dfrac x{(1-x^2)^3}$

$I=\displaystyle\int\frac{x^2}{(1+x^3)^2}\,\mathrm dx$

Sustituye:

$y=1+x^3\implies\mathrm dy=3x^2\,\mathrm dx$

$\implies I=\displaystyle\frac13\int\frac{\mathrm dy}{y^2}=-\frac1{3y}+C=-\frac1{3(1+x^3)}+C$

(Te dejaré confirmar por ti mismo.)

$I=\displaystyle\int\frac x{\sqrt{1-x^2}}\,\mathrm dx$

Sustituye:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{\sqrt y}=-\frac12(2\sqrt y)+C=-\sqrt{1-x^2}+C$

$I=\displaystyle\int\left(1+\frac1t\right)^3\frac{\mathrm dt}{t^2}$

Sustituye:

$u=1+\dfrac1t\implies\mathrm du=-\dfrac{\mathrm dt}{t^2}$

$\implies I=-\displaystyle\int u^3\,\mathrm du=-\frac{u^4}4+C=-\frac{\left(1+\frac1t\right)^4}4+C$

Podemos hacer que esto se vea un poco mejor:

$\left(1+\dfrac1t\right)^4=\left(\dfrac{t+1}t\right)^4=\dfrac{(t+1)^4}{t^4}$

$\implies I=-\dfrac{(t+1)^4}{4t^4}+C$

4 0

3 years ago

Which number is a solution of the inequality c > 5?<br><br> A) 2<br> B) 2.5<br> C) 5<br> D) 6.5

Reil [10]

Answer:

6.5

Step-by-step explanation:

4 0

3 years ago

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The ratio of boys to girls in Ms. smith’s class is 3 to 4. If there are 12 boys, how many girls are there?

Lorico [155]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ There will be 16 girls.

The relationship is x4. If we multiply 3 x 4, we get 12. What we do to one number we do to the other so 4 x 4 = 16.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

4 0

3 years ago

Which of the following is equivalent to 3^4?<br> 1. 12<br> 2. 81<br> 3. 7<br> 4. 64

Anna35 [415]

I think the answer is 12 because 3 times 4 is 12

3 0

3 years ago

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