What is the approximate molar mass of a molecular solute if 300 g of the solute in 1000 g of water causes the solution to have a

Question

Vaselesa [24]

3 years ago

15

What is the approximate molar mass of a molecular solute if 300 g of the solute in 1000 g of water causes the solution to have a

boiling point of 101°c? (kb = 0.512°c/m; kf = 1.86°c/m; molar mass of water = 18 g) 30 g 150 g 300 g 15 g?

Chemistry

2 answers:

mote1985 [20] · Answer 1 · 2022-07-17T05:02:51+03:00

mote1985 [20]3 years ago

8 0

The correct answer is 150g

valentina_108 [34] · Answer 2 · 2022-07-17T02:33:56+03:00

Answer is: <span>the approximate molar mass of a molecular solute is 150 g.
</span>m(molecular solute) = 300 g.
m(water) = 1000 g ÷ 1000 g/kg = 1 kg.
ΔT = 101°C - 100°C = 1°C.
M(molecular solute) = Kb · m(molecular solute) / m(water) · ΔT.
M(molecular solute) = 0,512°C/m · 300 g / (1 kg · 1°C).
M(molecular solute) = 153,6 g/mol.