If an element has 11 protons and 11 neutrons in its nucleus it
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Answer:
The pump work is 3451 kJ/s
Explanation:
Pump work (W) is calculated as
where
is the enthalpy of water at its final state
is the enthalpy of water at its initial state
is water mass flow
For liquids, properties are evaluated as saturated liquid. From the figure attached, it can be seen that
Replacing
Archimedes' principle allows us to find that the reasons why the thrust is not written when a body is in the air is:
- The thrust of air is about 800 times less than the thrust of a fluid
- In general the other forces (weight, tension) are much greater than thrust
Archimedes' principle establishes that the thrust is equal to the weight of the dislodged liquid (fluid)
B = ρ g V
Where B is the thrust, ρ and V the density and volume of the fluid, respectively, g the acceleration due to gravity.
In the attachment you have a diagram of a system in equilibrium in air and water, we can see that in the two cases for a system in equilibrium
B -W = 0
B = W
Let's find the value of the thrust in each case and compare
Used the density
Suppose that the volume of the two bodies is the same
r
We can see that the thrust in air or other gas is about 800 times less than the thrust in liquids. This is the reason that in many problems the thrust is not written when the body is in the air.
In conclusion, using Archimedes' principle, we find that the reason why the healed thrust is not written for a body is in the air is:
- The thrust of air is about 800 times less than the thrust of a fluid
- In general the other forces (weight, tension) are much greater than thrust
Learn more about Archimedes' principle here: