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-BARSIC- [3]
3 years ago
10

What are the square root of

t=" \sqrt{48} " align="absmiddle" class="latex-formula"> help mee please ​
Mathematics
2 answers:
PtichkaEL [24]3 years ago
6 0

<h3>Answer-</h3>

<h3>4√3 </h3>

<h3>Step by step explanation-</h3>

=\sqrt{2 \times 2 \times 2 \times 2 \times 3}

=\sqrt{2 {}^{2}  \times 2 {}^{2}  \times 3}

=2 \times 2 \sqrt{3}

= 4√3

<h3>So,The Answer is 4√3 .</h3>
Ray Of Light [21]3 years ago
5 0

\sqrt{48}  \\  =  \sqrt{2 \times 2 \times 2 \times 2 \times 3}  \\  =  \sqrt{ {2}^{2}  \times  {2}^{2}  \times 3}  \\  = 2 \times 2 \sqrt{3}  \\  = 4 \sqrt{3}

<h3>Your answer is 4√3.</h3>
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