Question

What are the square root of t=" \sqrt{48} " align="absmiddle" class="latex-formula"> help mee please ​

Answer 1

Answer-

4√3

Step by step explanation-

=$\sqrt{2 \times 2 \times 2 \times 2 \times 3}$

=$\sqrt{2 {}^{2} \times 2 {}^{2} \times 3}$

=$2 \times 2 \sqrt{3}$

$= 4√3$

So,The Answer is 4√3 .

Answer 2

$\sqrt{48} \\ = \sqrt{2 \times 2 \times 2 \times 2 \times 3} \\ = \sqrt{ {2}^{2} \times {2}^{2} \times 3} \\ = 2 \times 2 \sqrt{3} \\ = 4 \sqrt{3}$

Your answer is 4√3.