Answer:
v = 15.23 m/s
Explanation:
Given that,
Mass of a car, m = 1110 kg
Initial velocity, u = 21 m/s
Force,F = -8000 N
Time, t = 0.9 s
We need to find the final velocity of the car.
Force, F = ma

So, the final velocity of the car is 15.23 m/s.
Yes, Sliding Friction Stops a Car. When you apply the brakes of a car, sliding friction helps to stop it. ... The surface of the drum or rotor slide against the brake disc or pad, which is a force of friction that slows the vehicle down.
Answer:3W
If it takes an amount of work W to move two q point charges from infinity to a distance d apart from each other, then how much work should it take to move three q point charges from infinity to a distance d apart from each other?
A) 2W
B) 3W
C) 4W
D) 6W
Explanation: calculating work done,W, in moving two positive q point charges from infinity to a valued distance d from each other is
W = k(+q)(+q)/ d
k is couloumb's constant
work done in moving 3 equal positive charges from infinity to a finite distance is given by
W₂=W₄=W₆=k(+q)(+q)/ d
Total work done, W' =k(+q)(+q)/ d + k(+q)(+q)/ d + k(+q)(+q)/ d
= W + W + W = 3W
Answer:
el monitor,las impresoras y las memorias portátiles
Answer:
The mass of Laura and the sled combined is 887.5 kg
Explanation:
The total force due to weight of Laura and friction on the sled can be calculated as follows;

= (400 + 310) N
= 710 N
From Newton's second law of motion, "the rate of change of momentum is directly proportional to the applied force.

where;
is mass of Laura and
is mass of sled
Mass of Laura and the sled combined is calculated as follows;

given
V = Δv = 4-0 = 4m/s
t = 5 s

Therefore, the mass of Laura and the sled combined is 887.5 kg