Question

If a body moves in a rectangular path ABCD of length 3m and width 5m. Calculate both distance travelled and displacement

Answer 1

For a rectangular path, two sides opposite each other is equal
The distance round ABCD indicates perimeter(P) of rectangle

P = 2L+ 2B
P = 2(3)+ 2(5)
P= 6 + 10
P= 16cm

For displacement is the how far an object is from the original position and since it came back to the original position, the displacement is 0cm

Answer 2

• Displacement =0(As it came back to initial position.

Distance=Perimeter of rectangle.

$\\ \rm\longmapsto 2(L+B)$

$\\ \rm\longmapsto2(3+5)$

$\\ \rm\longmapsto 2(8)$

$\\ \rm\longmapsto 16m$