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luda_lava [24]
2 years ago
7

The movie "The Gods Must Be Crazy" begins with a pilot dropping a bottle out of an airplane. A surprised native below, who think

s it is a message from the gods, recovers it. If the plane from which the bottle was dropped was flying at a height of 500 m, and the bottle lands 400 m horizontally from the initial dropping point, how fast was the plane flying when the bottle was released? Draw a 2-dimensional motion map for the velocities and another for the acceleration.
Physics
1 answer:
Sergio039 [100]2 years ago
8 0

Answer:

⇔⇔⇔↑∑∑∩∅¬⊕║⊇↔∴∉∵

Explanation:

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Anna71 [15]

The answer is above but I don't know if it's correct.

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1 year ago
if an object is thrown straight up with an initial velocity of 8m/s and takes 3 seconds to strike the ground, from what height w
KatRina [158]

Answer:

s = it+1/2 at²

s= 8×3+1/2 (10)(3)²

s = 24+45

s= 69

the object was thrown from a height of 69 meters

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2 years ago
The force of gravitation between two spherical bodies is Gm1 m2 /r2, where r is separation between their dash
AnnZ [28]

Explanation:

F = Gm1m2/r^2

kya nikalna hai bhai isme

6 0
3 years ago
Read 2 more answers
The kinetic friction force between a 60.0-kg object and a horizontal surface is 50.0 N. If the initial speed of the object is 25
Vikki [24]

Answer:

375 m.

Explanation:

From the question,

Work done by the frictional force = Kinetic energy of the object

F×d = 1/2m(v²-u²)..................... Equation 1

Where F = Force of friction, d = distance it slide before coming to rest, m = mass of the object, u = initial speed of the object, v = final speed of the object.

Make d the subject of the equation.

d = 1/2m(v²-u²)/F.................. Equation 2

Given: m = 60.0 kg, v = 0 m/s(coming to rest), u = 25 m/s, F = -50 N.

Note: If is negative because it tends to oppose the motion of the object.

Substitute into equation 2

d = 1/2(60)(0²-25²)/-50

d = 30(-625)/-50

d = -18750/-50

d = 375 m.

Hence the it will slide before coming to rest = 375 m

6 0
3 years ago
A satellite with a mass of 110 kg and a kinetic energy of 3.0 ´ 109 J must be moving at a speed of
djverab [1.8K]

Answer: A satellite with a mass of 110 kg and a kinetic energy of 3.08×10^9 J must be moving at a speed of 7483 m/s.

Explanation: To find the answer we need to know about the kinetic energy of a body.

<h3>How to solve the problem the equation of kinetic energy?</h3>
  • We have the expression for kinetic energy of a body as,

                                   KE=\frac{1}{2}mv^2

  • Given that,

                                   m=110kg\\KE=3.08*10^9J\\

  • We have to find the speed of the satellite,

                               v=\sqrt{\frac{2KE}{m} } =\sqrt{\frac{2*3.08*10^9}{110} } =7.483*10^3 m/s

Thus, we can conclude that, the velocity of the satellite will be 7438m/s.

Learn more about Kinetic energy here:

brainly.com/question/28105739

#SPJ4

8 0
1 year ago
Read 2 more answers
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