The answer is above but I don't know if it's correct.
Answer:
s = it+1/2 at²
s= 8×3+1/2 (10)(3)²
s = 24+45
s= 69
the object was thrown from a height of 69 meters
Explanation:
F = Gm1m2/r^2
kya nikalna hai bhai isme
Answer:
375 m.
Explanation:
From the question,
Work done by the frictional force = Kinetic energy of the object
F×d = 1/2m(v²-u²)..................... Equation 1
Where F = Force of friction, d = distance it slide before coming to rest, m = mass of the object, u = initial speed of the object, v = final speed of the object.
Make d the subject of the equation.
d = 1/2m(v²-u²)/F.................. Equation 2
Given: m = 60.0 kg, v = 0 m/s(coming to rest), u = 25 m/s, F = -50 N.
Note: If is negative because it tends to oppose the motion of the object.
Substitute into equation 2
d = 1/2(60)(0²-25²)/-50
d = 30(-625)/-50
d = -18750/-50
d = 375 m.
Hence the it will slide before coming to rest = 375 m
Answer: A satellite with a mass of 110 kg and a kinetic energy of 3.08×10^9 J must be moving at a speed of 7483 m/s.
Explanation: To find the answer we need to know about the kinetic energy of a body.
<h3>
How to solve the problem the equation of kinetic energy?</h3>
- We have the expression for kinetic energy of a body as,


- We have to find the speed of the satellite,

Thus, we can conclude that, the velocity of the satellite will be 7438m/s.
Learn more about Kinetic energy here:
brainly.com/question/28105739
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