Explanation:
K.E = 5,000,000 KJ
MASS = 100,000,000 Kg
K.E = 1/2 MV^2
therefore
v = 0.316 m/s^2
A thunderstorm loses energy in the _______ stage.
2 answers:
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Answer:
t = o.6 s
Explanation:
Let ball thrown from below be A and ball dropped from above be B.
A and B meet when they both are same level above the ground. Then let A moved up a distance d and B dropped a distance h. Then you know
d + h = 15 m ---------------(1)
Now apply s = ut + at²
To A upwards,
d = 25t - gt² -----------------(2)
To B downwards,
h = 0 + gt² ----------------(3)
(1) = (2) + (3) ⇒ 15 = 25t
t = 0.6 s