The answer is:
The first option, the amount dumped after 5 days is 0.166 tons.
<h2>Why?</h2>To solve the problem, we need to integrate the given expression and evaluate using the given time.
So, integrating we have:
Hence, we have that the amount dumped after 5 days is 0.166 tons.
Have a nice day!
Answer:
The degrees of freedom are given by:
The p value for this case is given by:
And for this case the p value is lower than the significance level so we have enough evidence to reject the null hypothesis and then we can conclude that true mean is higher than 55.
Step-by-step explanation:
Information given
We have the following data: 54 55 58 59 59 60 61 61 62 65
The sample mean and deviation can be calculated with the following formulas:
represent the sample mean
represent the sample standard deviation
sample size
represent the significance level
t would represent the statistic
represent the p value
System of hypothesis
We want to test if the true mean is higher than 55, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
Replacing the info given we got:
(1)
And replacing the info given we got:
The degrees of freedom are given by:
The p value for this case is given by:
And for this case the p value is lower than the significance level so we have enough evidence to reject the null hypothesis and then we can conclude that true mean is higher than 55
