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Lilit [14]
3 years ago
14

What is the molarity of a stock solution if 60 mL were used to make 150 mL of a .5M solution

Chemistry
1 answer:
kirza4 [7]3 years ago
6 0

Answer:

The answer to your question is 1.25 M

Explanation:

Data

Molarity 1 = ?

Volume 1 = 60 ml

Molarity 2 = 0.5 M

Volume 2 = 150 ml

Process

1.- Write the dilution formula

       Molarity 1 x Volume 1 = Molarity 2 x Volume 2

-Solve for Molarity 1

       Molarity 1 = Molarity 2 x Volume 2 / Volume 1

-Substitution

        Molarity 1 = (0.5)(150) / 60

-Simplification

        Molarity = 75 / 60

-Result

        Molarity = 1.25 M

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Lelechka [254]

Using the Rydberg formula, the spectral line of H - atom is suitable for this purpose is Paschen, ∞ → 3.

  • Using the Rydberg formula;

1/λ = RH(1/nf^2 - 1/ni^2)

Given that;

λ = wavelength

RH = Rydberg constant

nf = final state

ni = initial state

  • When final state = 3 and initial state = ∞

Then;

1/λ =  1 × 10^7 m-1 (1/3^2 - 1/ ∞^2)

1/λ =  1 × 10^7 m-1 (1/3^2 )

λ = 900 nm

Hence, the correct answer is Paschen, ∞ → 3

Learn more about the Rydberg formula; brainly.com/question/17753747

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Calculate the fractional saturation for hemoglobin when the partial pressure of oxygen is 58 mm Hg. Assume hemoglobin is 50% sat
svetlana [45]

Answer:

0.8988

Explanation:

To calculate the fractional saturation of hemoglobin , the formula used is

YO_2=\frac{(pO_2)^n}{(p50)^n+(pO_2)^n}

now putting the values

YO_2= \frac{58^3}{28^3+58^3}

= \frac{195112}{21952+195112}

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Therefore, fractional saturation of hemoglobin= 0.8988

where

YO_2= fractional saturation of hemoglobin

pO_2= partial pressure of oxygen

p50= is the pO_2 at which hemoglobin is 50% saturated

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Answer:

In the oxide form, uranium can be disposed of as low-level radioactive waste at an approved disposal facility. Approximately 350,000 tons of anhydrous HF are used annually in the United States.

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