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kherson [118]
4 years ago
7

Snow has been lying on a mountainside. Suddenly, it starts to move down the mountain. Which types of friction are observed in th

is avalanche? Where does each type occur?
Physics
1 answer:
Alexus [3.1K]4 years ago
8 0
<h2>Snow starts to move down the mountain </h2>

The energy which is due to position is potential energy. So when the snow is lying on the mountain. It possess potential energy but when suddenly, it starts to move down the mountain, the potential energy is converted into the kinetic energy. Yet some force is exerting on the snow to stop the smooth flow of snow through mountains.

This example of frictional force may be due to presence of rough surface or stones. Generally, there are four types of friction as static, rolling, sliding and fluid friction. Though in this case when snow is lying it possess static friction, when flows then it possesses sliding and fluid friction both.

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What is the electric field 4.0 m from the center of the terminal of a Van de Graaff with a 7.10 mC charge, noting that the field
Jobisdone [24]

Answer:

3984875 N/C

Explanation:

Applying,

E = kq/r².................. Equation 1

Where E = Electric field, q = charge, r = distance, k = coulomb's constant.

From the question,

Given: q = 7.10 mC = 0.0071 C, r = 4.0 m

Constant: k = 8.98×10⁹ Nm²/C²

Substitute these values into equation 1

E = 0.0071(8.98×10⁹)/4²

E = 3984875 N/C

Hence the electric field is 3984875 N/C

5 0
3 years ago
When they are far apart, the momentum of a proton is 3.2 ✕ 10−21, 0, 0 kg · m/s as it approaches another proton that is initiall
Rina8888 [55]
<span>(6.0x10^-22, -1.40x10^-21, 0) kg*m/s Momentum is a conserved quantity. The total momentum of the system before and after the interactions will not change. So, let's look at the momentum before the interaction. (3.2x10^-21, 0, 0) kg*m/s and (0,0,0) kg*m/s After the interaction (2.6x10^-21, 1.40x10^-21, 0) kg*m/s and the other proton has to have a momentum that when added to this momentum equal the original value. Since the y and z vectors were initially 0, all we need for the y and x vector values of the result is to negate them. The x vector value will be 3.2x10^-21 - 2.6x10^-21 = 0.6x10^21 = 6.0x10^-22. So the other proton will have a momentum of (6.0x10^-22, -1.40x10^-21, 0) kg*m/s</span>
5 0
4 years ago
What property of a solid would be most important if you were calculating how much paint was required to cover it?
Nadusha1986 [10]
Define shape and volume

Because: The area of the shape is how much paint would cover the object
6 0
3 years ago
Is kinetic energy scalar quantity
VashaNatasha [74]

Yes, Kinetic Energy is a scalar quantity because the direction is not needed.  A scalar quantity is one dimensional measurement.

Explanation:

  • Kinetic Energy is a scalar quantity that means it has only a magnitude and no direction.
  • Energy has a size but no direction; two objects can have the same kinetic energy but they travel in opposite directions.
  • The formula of Kinetic Energy is
  1. K.E = \frac{1}{2} mv^{2}
  • Mass is a scalar quantity and velocity is a vector quantity.
  • squaring velocity will make vector to scalar quantity.
5 0
3 years ago
Read 2 more answers
Calculate the force on the test charge by the +6μC charge. Hint: The force in the positive x-direction is positive and the neg
DIA [1.3K]

Answer:

The force on the test charge is 114.75 N.

Explanation:

Given that,

Test charge q=6\ \mu C

Suppose the test charge is 3.4 μC and the distance between the charge and test charge is 4.0 cm.

We need to calculate the force on the test charge

Using formula of electric force

F=\dfrac{kqq_{1}}{r^2}

Where, q = test charge

q₁ =charge

r = distance

Put the value into the formula

F=\dfrac{9\times10^{9}\times6\times10^{-6}\times3.4\times10^{-6}}{(4.0\times10^{-2})^2}

F=114.75\ N

Hence, The force on the test charge is 114.75 N.

6 0
4 years ago
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