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Blizzard [7]
4 years ago
9

If sonic the hedgehog runs 40 meters in 5 seconds, what is his speed?

Physics
1 answer:
hoa [83]4 years ago
6 0

Answer:

8m/s

Explanation:

Sonic can go WAAAAAAAAAAAAY faster, but he must be taking a jog. All jokes aside, Divide 40 by 5. You get 8 meters per second or 17.9 mph.

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In what way do pigments act differently from light?
Karo-lina-s [1.5K]
A. Because they reflect their color and absorb all the others
6 0
4 years ago
Read 2 more answers
Latency refers to the 27 seconds of time it takes for someone to refocus on driving after they finish texting or talking on the
Alexxandr [17]

The term "latency" describes the 27 seconds that pass after someone has finished texting or conversing on the phone before they can concentrate again on driving. The given statement is true.

<h3>What is latency?</h3>

A measure of delay is latency. The amount of time it takes for some data to travel across a network is known as latency.

The amount of time it takes for information to travel from its source to its destination and back is often quantified as a round trip delay.

The 27 seconds that pass after someone has done texting or talking on the phone before they can focus on driving again are referred to as "latency." The assertion is accurate.

Hence, the given statement is true.

To learn more about the latency refer to;

brainly.com/question/14264521

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6 0
2 years ago
Peter designed a road with a curve of radius 30 m that is banked so that a 950 kg car traveling at 40.0 km/h can round it even i
spayn [35]

Answer:

v = 15.56 m/s

v = 56 km/h

Explanation:

When coefficient of friction is approximately zero then we have

F_ncos\theta = mg

F_n sin\theta = \frac{mv^2}{R}

tan\theta = \frac{v^2}{Rg}

here we know that

v = 40 km/h = 11.11 m/s

R = 30 m

tan\theta = \frac{11.11^2}{30\times 9.81}

\theta = 22.75 degree

now when friction coefficient is 0.30 then we have

F_n cos\theta = mg + F_f sin\theta

F_f cos\theta + F_n sin\theta = \frac{mv^2}{R}

now we have

v = \sqrt{Rg(\frac{\mu + tan\theta}{1 - \mu tan\theta})}

v = \sqrt{30(9.81)(\frac{0.30 + tan22.75}{1 - (0.30) tan22.75})}

v = 15.56 m/s

v = 56 km/h

3 0
3 years ago
A cart is pulled by a force of 250 N at an angle of 35° above the horizontal. The cart accelerates at 1.4 m/s2. The free-body di
Vikki [24]

Answer:

Mass of the cart = 146 kg

Explanation:

A cart is pulled by a force of 250 N at an angle of 35° above the horizontal.

The cart accelerates at 1.4 m/s² horizontally.

Horizontal force = Fcosθ = 250 cos35° = 204.79N

We have F = ma

Substituting

        204.79 = m x 1.4  

              m = 146.28 kg = 146 kg

Mass of the cart = 146 kg

3 0
3 years ago
While traveling along a highway a driver slows from 34 m/s to 17 m/s in 6 seconds. What is the automobiles acceleration?​
xxTIMURxx [149]

Answer:

-2.83 m/s²

Explanation:

  • Initial velocity (u) = 34 m/s
  • Final velocity (v) = 17 m/s
  • Time taken (t) = 6 seconds

❖ Acceleration is defined as the rate of change in velocity with time.

→ a = (v - u)/t

  • v denotes final velocity
  • a denotes acceleration
  • u denotes initial velocity
  • t denotes time

→ a = (17 - 34)/6 m/s²

→ a = -17/6 m/s²

<h3>→ Acceleration = -2.83 m/s²</h3>

(Minus sign implies that the velocity is decreasing.)

5 0
3 years ago
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