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Blizzard [7]
3 years ago
9

If sonic the hedgehog runs 40 meters in 5 seconds, what is his speed?

Physics
1 answer:
hoa [83]3 years ago
6 0

Answer:

8m/s

Explanation:

Sonic can go WAAAAAAAAAAAAY faster, but he must be taking a jog. All jokes aside, Divide 40 by 5. You get 8 meters per second or 17.9 mph.

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I'm confusion, can I please get help???
kotykmax [81]

Answer:

Anything below 7.0 is acidic, so the range would be 0 to 7.

Neutral is simply 7, in the middle of the scale.

Lastly, anything above 7.0 is basic or alkaline, so that would be 7 to 14.

Good luck, I hope this helps

7 0
3 years ago
Section 2.2
Feliz [49]

Answer:

Speed changes at the rate of 24 m/s for each second over time.

Explanation:

We are told the object's acceleration is equal to 24 m/s²

Now we know that acceleration can also be defined as the rate of change of speed with time. Also speed has a unit known as m/s.

Thus, we can rephrase the acceleration in this question to mean;

Speed changes at the rate of 24 m/s for every second with time.

6 0
3 years ago
A mechanic changing the spark plugs in a car notes that the instruction manual calls for a torque with a magnitude of
Papessa [141]

The magnitude (in N) of the force she must exert on the wrench is 150.1 N.

<h3>Force exerted by the wrench</h3>

The force exerted by the wrench is calculated using torque formula as follows;

torque, τ = F x r x sinθ

where;

  • F is the applied force
  • r is the perpendicular distance if force applied

F =  τ /(r sinθ)

F = (39) / (0.3 sin 60)

F = 150.1 N

Thus, the magnitude (in N) of the force she must exert on the wrench is 150.1 N.

Learn more about torque here: brainly.com/question/14839816

#SPJ1

5 0
2 years ago
Convert 55 miles into inches
frosja888 [35]

Answer:

3.485e+6 inches. hope this helps

6 0
2 years ago
Read 2 more answers
An 80-cm-long steel string with a linear density of 1.0 g/m is under 200 N tension. It is plucked and vibrates at its fundamenta
icang [17]

Answer:

Wavelength of the sound wave that reaches your ear is 1.15 m

Explanation:

The speed of the wave in string is

v=\sqrt{\frac{T}{\mu} }

where T= 200 N is tension in the string , \mu=1.0 g/m is the linear mass density

v=\sqrt{\frac{200}{1\times 10^{-3} }

v=447.2 m/s

Wavelength of the wave in the string is

\lambda =2L=2\times 0.8=1.6 m

The frequency is

f=\frac{v}{\lambda} \\f=\frac{447.2}{1.6}\\f=298.25 Hz

The required wavelength pf the sound wave that reaches the ear is( take velocity of air v=344 m/s)

\lambda=\frac{v_{air}}{f} \\\lambda=\frac{344}{298.25} \\\lambda=1.15 m

8 0
3 years ago
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