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3 years ago

5

tessa can now use her graph in the example to find the coordinates of the vertices of figure G'H'I'J. How could she have founf t

hese coordinates without drawing the reflection of figure GHIJ?

1 answer:

Nadusha1986 [10]3 years ago

7 0

Answer:

Step-by-step explanation:

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Morgarella [4.7K]

Answer:

$(y-1)=\frac{3}{2}(x+3)$

Step-by-step explanation:

The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=-3\\y_1=1$ . We write

$(y-1)=m(x--3)\\(y-1)=m(x+3)$

Since the line is parallel to the line shown it will have the same slope. To find m, count the slope from each marked point on the graph. Count the rise then the run and create a fraction rise/run. The slope is 6/4 which simplifies to 3/2. Now substitute it for m.

$(y-1)=\frac{3}{2}(x+3)$

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notka56 [123]

Answer:

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Step-by-step explanation:

$h = ac + mn$

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