Answer:
your answer would be -13.8y
Answer:
c = -24
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
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Step-by-step explanation:
<u>Step 1: Define</u>
6c - 1 - 4c = -49
<u>Step 2: Solve for </u><em><u>c</u></em>
- Combine like terms: 2c - 1 = -49
- Isolate <em>c</em> term: 2c = -48
- Isolate <em>c</em>: c = -24
All you need to do is plug -5 into the second equation and you see it is near (-5, -8). When plugged into the top, you get (-5, -27/4) which comes out to ABOUT -6.75 for the Y value. The closest is actually a tie. The first option is .8 from the first and .45 from the second leading in a total distance of 1.25. The second, which is the fellow answer, is 1.2 from the first and .05 from the second, leading to 1.25 away.
The third, which is next closest is 1.8 from the first and .55 from the second leading to a distance of over 2 from the optimal, so only the first two are answers.
Answer:
A= 0,2
B= 0,2
C= 0,4
D=0,2
Step-by-step explanation:
We know that only one team can win, so the sum of each probability of wining is one
P(A)+P(B)+P(C)+P(D)=1
then we Know that the probability of Team A and B are the same, so
P(A)=P(B)
And that the the probability that either team A or team C wins the tournament is 0.6, so P(A)+Pc)= 0,6, then P(C)= 0.6-P(A)
Also, we know that team C is twice as likely to win the tournament as team D, so P(C)= 2 P(D) so P(D) = P(C)/2= (0.6-P(A))/2
Now if we use the first formula:
P(A)+P(B)+P(C)+P(D)=1
P(A)+P(A)+0.6-P(A)+(0.6-P(A))/2=1
0,5 P(A)+0.9=1
0,5 P(A)= 0,1
P(A)= 0,2
P(B)= 0,2
P(C)=0,4
P(D)=0,2
The answer is D, none of these
