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Tomtit [17]
2 years ago
7

An electric pole shown in the figure below supports a power line that passes through it. A cable tied to the pole at B passes th

rough a hole in the struct at C and is then tied to the ground at B. There is no friction between the struct and cable. What is the force exerted by the cable onto the pole at B, if the tension in the cable is 47lb.

Physics
1 answer:
nikdorinn [45]2 years ago
3 0

We have that The force exerted by the cable at point B on the pole is

T_1=60.189ib

From the Diagram

We can see that A,B.C is the area showing the circumference of a cable(power line)

\sum F_y=0\\\\

T_1sin51.34=47

Generally the equation for the Tension  is mathematically given as

T_1=60.189ib

In conclusion

The force exerted by the cable at point B on the pole is

T_1=60.189ib

For more information on this visit

brainly.com/question/12534911?referrer=searchResults

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The AC voltage source is connected to an inductor and a resistor in series. If the frequency of the source is increased the curr
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Answer:

If the frequency of the source is increased the current in the circuit will decrease.

Explanation:

The current through the circuit is given as;

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I = \frac{V}{\sqrt{R^2 + (2\pi fL)^2} }

From the equation above, an increase in frequency (f) will cause a decrease in current (I).

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The force of an electric field is proportional to to electric charge? True or False
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3 0
2 years ago
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A particle has a charge of +1.5 µC and moves from point A to point B, a distance of 0.15 m. The particle experiences a constant
kirill [66]

Answer:

Part a)

F = 6 \times 10^{-3} N

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E = 4000 N/C

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As we know that the change in electric potential energy is equal to the work done by electric field

W = EPE_A - EPE_B

W = 9.0 \times 10^{-4} J

now from the equation of work done we know that

W = F.d

(9.0 \times 10^{-4}) = F(0.15)

F = 6 \times 10^{-3} N

Direction of force is along the motion of charge

Part b)

As we know the relation between electrostatic force and electric field given as

F = qE

(6 \times 10^{-3}) = 1.5 \times 10^{-6} E

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8 0
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two horses are pulling a 325 kg wagon, initially at rest. The horses exert 250 N and 178 N forward forces, respectively. Ignorin
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Answer:

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Therefore, the acceleration from Newton's 2nd Law is:

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7 0
3 years ago
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