The first time we read this, we think that we'll have to go look up a bunch of stuff about the gravitational constant, centripetal force, orbital mechanics, the Moon's period of revolution, and who knows whut owl !
But you know whut ? The only thing we need is Newton's 2nd law:
F = m A
Divide each side by m :
Acceleration = Force / mass
Acceleration = (2.03 x 10²⁰ Newtons) / (7.35 x 10²² kg)
Acceleration = (2.03 x 10²⁰ / 7.35 x 10²² kg) (m/s²)
<em>Acceleration = 0.00276 m/s²</em>
Answer:C
Explanation:
Given
mass 
is at 
mark
mass 
is at 
mark
Scale is Pivoted at 
For scale to be in equilibrium net torque must be equal to zero
Taking ACW as positive thus
Therefore a net torque of 0.04 g is required in CW sense which a mass 
can provide at a distance of 
from pivot
therefore in meter stick it is at a distance of 
<u>Answer</u>
1.667 m/s²
Using the Newton's second law of motion;
force is directly proportional to the rate of change of momentum and it takes place in the direction of force.
i.e F = change in momentum
F = (mv - mu)/t
=m(v-u)/t
= ma
∴ F =ma
a = F/m
= 150/90
= 1.667 m/s²
