Answer:
The answer to the question is
The correct weight of the former student = 116 lbf
Explanation:
To solve the question, we list out the known variables as follows
Capacity of the scale = 120 lbs
Capacity of the spring dynamometer = 20 lbs
Reading on the scale = 100lb
Reading on the spring dynamometer= 16 lb
at equilibrium, sum of forces = 0
Therefore weight of former student = reaction forces of the scale + the reaction force of the spring dynamometer = 100lb + 16 lb = 116 lb
The correct weight = 116lb weight or 52.62 kg
Converting to weight which is a force = mass * acceleration = 52.62 kg * 9.81 m/s² =
516.2 N = 116 lbf
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I cant really say but i believe it is called extinction
Answer:
0.0816 kgm/s
Explanation:
From the question,
Momentum of the pellet just before it hits the modelling clay is = (mass of the pellet+ mass of the truck clay)×initial velocity of pellet.
P =(M+m)u...................... Equation 1
Where P = initial momentum of the pellet, m = mass of the pellet, u = initial speed of the pillet, M = mass of the truck
Given: m = 2 g = 2/1000 kg = 0.002 kg, u = 0.8 m/s, M = 0.1 kg
Substitute these values into equation 1
P = (0.002+0.1)0.8
P = (0.102)0.8
P = 0.0816 kgm/s