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ziro4ka [17]
3 years ago
10

At what age is a child likely to learn to sit up without support?

Physics
1 answer:
Gemiola [76]3 years ago
4 0

Answer by YourHope:


Hi! ^-^


At what age is a child likely to learn to sit up without support?


I would say Five months if you position the child but Nine months for the baby to sit up by themselves! So the answer is Nine months!


Have a BEAUTIFUL day~

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This questic concerns a tablet that
Vanyuwa [196]

Answer:

The remaining percentage of drug concentration is about 88.7% 2 years after manufacture.

Explanation:

Recall the formula for the decay of a substance at an initial N_0 concentration at manufacture:

N(t)=N_0\,e^{-k\,\,t}

where k is the decay rate (in our case 0.06/year), and t is the elapsed time in years. Therefore, after 2 years since manufacture we have:

N=N_0\,e^{-0.06\,\,(2)}\\N=N_0\,e^{-0.12}\\N/N_0=e^{-0.12}\\N/N_0=0.8869

This in percent form is 88.7 %. That is, the remaining percentage of drug concentration is about 88.7% 2 years after manufacture.

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3 years ago
An airplane flew 1000 m in 400 seconds. What is the airplane's speed?
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Answer:

speed =  \frac{distance}{time}  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   =  \frac{1000}{400}  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = 2.5m {s}^{ - 1}

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How many atoms of carbon would two molecules of glucose (C6H12O6) have?
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The correct response would be B. 12.
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Astronomers define the __________ as all of space and everything in it. It is enormous, almost beyond imagination. Question 2 op
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I took the quiz.

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3 years ago
A bat emitts a sonar sound wave (343 m/s) that bounces off a mosquito 8.42 m away
Varvara68 [4.7K]

The time lapse between when the bat emits the sound and when it hears the echo is 0.05 s.

From the question given above, the following data were obtained:

Velocity of sound (v) = 343 m/s

Distance (x) = 8.42 m

Time (t) =?

We can obtain obtained the time as illustrated below:

v = 2x / t

343 = 2 × 8.42 / t

343 = 16.84 / t

Cross multiply

343 ×  t = 16.84

Divide both side by 343

t = 16.84/343

t = 0.05 s

Thus, the time between  when the bat emits the sound and when it hears the echo is 0.05 s.

<h3>How does a bat know how far away something is?</h3>

A bat emits a sound wave and carefully listens to the echoes that return to it. The returning information is processed by the bat's brain in the same way that we processed our shouting sound with a stopwatch and calculator. The bat's brain determines the distance of an object by measuring how long it takes for a noise to return.

Learn more about time elapses between when the bat emits the sound :

<u>brainly.com/question/16931690</u>

#SPJ4

Correction question:

A bat emits a sonar sound wave (343 m/s) that bounces off a mosquito 8.42 m away. How much time elapses between when the bat emits the sound and when it hears the echo? (Unit = s)

8 0
2 years ago
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