Answer: scenario b and scenario c uses most power
Explanation:
Scenario a:
Work=120J
Time=8 seconds
Power=work ➗ time
Power=120 ➗ 8
Power=15
Power=15 watts
Scenario b:
Work=160J
Time=8 seconds
Power=work ➗ time
Power=160 ➗ 8
Power=20
Power =20 watts
Scenario c:
Work=200J
Time=10 seconds
Power= work ➗ time
Power=200 ➗ 10
Power=20
Power=20 watts
Scenario b and scenario c uses most power
Answer:
magnitude is 1382.59 N/C
Explanation:
Given the data in the question;
The time taken is;
t = x / v
we substitute;
t = ( 2 × 10⁻²) / ( 5.69 × 10⁶ )
t = 3.5149 × 10⁻⁹ s
next, the acceleration is;
a = 2y/t² = [2( 0.150 × 10⁻²)] / [ ( 3.5149 × 10⁻⁹ )² ]
a = 2.42826 × 10¹⁴ m/s²
now, the electric field is;
E = ma / q
we know that;
mass of electron m = 9.11 × 10⁻³¹ kg,
charge of electron q = 1.60 × 10⁻¹⁹ coulomb
we substitute
E = ( 9.11 × 10⁻³¹ )(2.42826 × 10¹⁴) / 1.60 × 10⁻¹⁹
E = 2.21214 × 10⁻¹⁶ / 1.60 × 10⁻¹⁹
E = 1.3826 × 10²¹
E = 1382.59 N/C
Therefore, magnitude is 1382.59 N/C
If they have the same momentum, then
m₁ v₁ = m₂ v₂
If m₁ > m₂, then we must have v₁ < v₂ to preserve the equality.
The object with the larger speed - the second object - thus has more kinetic energy.
Answer:
14 μm
Explanation:
The magnetic field due to a long straight wire is B = μ₀i/2πr where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, i = current = 7.0 A and r = distance of credit card from magnetic field.
So r = μ₀i/2πB since B = 1000 gauss = 1000 G × 1 T/10000 G = 0.1 T
r = 4π × 10⁻⁷ H/m × 7.0 A/(2π × 0.1 T)
r = 2 × 10⁻⁷ H/m × 7.0 A/0.1 T
r = 14 × 10⁻⁷ H/m × A/0.1 T
r = 140 × 10⁻⁷ m
r = 1.4 × 10⁻⁵ m
r = 14 × 10⁻⁶ m
r = 14 μm
