For this problem, we use the conservation of momentum as a solution. Since momentum is mass times velocity, then,
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
where
v₁ and v₂ are initial velocities of cart A and B, respectively
v₁' and v₂' are final velocities of cart A and B, respectively
m₁ and m₂ are masses of cart A and B, respectively
(7 kg)(0 m/s) + (3 kg)(0 m/s) = (7 kg)(v₁') + (3 kg)(6 m/s)
Solving for v₁',
v₁' = -2.57 m/s
<em>Therefore, the speed of cart A is at 2.57 m/s at the direction opposite of cart B.</em>
Answer: 0.3872m
Explanation:
q= 100nC --> 100x10^-9 C
k= 9x10^9 Nm^2/C^2
E= 6kN/C --> 600 N/C
r=?
--> 
Despejas "r"
Resuelves
<h3>
(la x es por, no es una variable)</h3><h3>r= 0.3872983346m</h3>
Answer:
0.42°
Explanation:
Using Snell's law of refraction which states that the ratio of the angle of sin of incidence to angle of sine of refraction is equal to a constant for a given pair of media. Mathematically,
Sin(i)/sin(r) = n
n is the refractive index of the medium
FOR VIOLET LIGHT:
n = 2.46
i = 51°
r = ?
To get r, we will use the Snell's law formula.
2.46 = sin51°/sinr
Sinr = sin51°/2.46
Sinr = 0.316
r = sin^-1(0.316)
rv = 18.42°
FOR RED LIGHT:
n = 2.41
i = 51°
r = ?
To get r, we will use the Snell's law formula.
2.41 = sin51°/sinr
Sinr = sin51°/2.41
Sinr = 0.323
r = sin^-1(0.323)
rd = 18.84°
The angular separation between these two colors of light in the refracted ray will be the difference between there angle of refraction.
Angular separation = rd - rv
= 18.84° - 18.42°
= 0.42°
Answer:
The centripetal acceleration of the object is 
.
Explanation:
We have,
Radius of a circular path is 200 m
It takes 5 seconds to complete 10 revolutions. The angular velocity of the object is given by the rate of change of angular displacement per unit time :
The centripetal acceleration of the object is given by :
So, the centripetal acceleration of the object is .
i believ that the answer would be
the acceleration of B is 0.2
