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2 years ago

9

An experienced computer technician can set up a network in 12 hours. It would take an intern 20 hours to set up the same network

. What is the rate of the experienced technician?
A.) 1/12
B.) x/12

1 answer:

Lena [83]2 years ago

7 0

Answer:

in my own opinion the answer is is 1/12

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I need help please it’s due today I forgot how to do this :(

choli [55]

Answer:

Samantha payed 12.71$ for her purchase.

Step-by-step explanation:

I may have misunderstood the question, but it looks like you can use a calculator for this!

6.19 + 2.85 + 2.29 + 1.38 =

12.71

8 0

3 years ago

Please help with the problem

worty [1.4K]

Answer:

95%

Step-by-step explanation:

0.6 of 40 is 24, she bought 24 green balloons.

24 × 1.5 = 36, she bought 36 yellow balloons.

So we have

40 red

24 green

36 yellow

Then from the rest of the information, 2 red, 2 green, and 1 yellow balloon all popped.

We now have

38 red

22 green

35 yellow

for a total of:

95 balloons out of 100 original balloons, 95%

7 0

2 years ago

Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag

VLD [36.1K]

$Hey~freckledspots!\\----------------------$

$We~will~solve~for~i^{425}!$

$Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\$

$Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------$

$Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------$

$Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------$

$Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------$

$Answer:\\\large\boxed{-1+i}\\----------------------$

$Hope~This~Helped!~Good~Luck!$

8 0

3 years ago

Read 2 more answers

A college student has 700$ in their account she spends $165 from the account on books and then deposits $190 in the account how

adell [148]

Hello,

I hope so far you and your family are staying safe and healthy!

We need to solve this step by step.

The college student has $700 in their account. But then she spends $165 on books from that money. So we need to Subtract that.

700 - 165 =535

However, later on, she deposits $190 to the same account. So we need to take the remain we had and add it to the new amount.

535 + 190 = 725

Thus,

There are $725 in the account.

I wish you all the best!

~Gary

4 0

2 years ago

What is 12 ÷ 1 1/5 ?

masya89 [10]

Answer:

10

Step-by-step explanation:

12 ÷ 1 1/5

Change to an improper fraction

12 ÷ ( 5*1+1)/5

12 ÷ 6/5

Copy dot flip

12 * 5/6

12/6 * 5

2*5

10

3 0

3 years ago

Read 2 more answers