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3 years ago

Which of the following correctly describes a compound?

Chemistry

2 answers:

Oksi-84 [34.3K]3 years ago

7 0

I think its c, it makes sense to me to be c

statuscvo [17]3 years ago

4 0

Answer: Option (C) is the correct answer.

Explanation:

A compound is a substance that contains atoms of two or more different elements which are chemically combined together in a fixed ratio by mass.

For example, NaCl, $CO_{2}$ , $Mg(OH)_{2}$ etc are all compounds.

Atoms of a compound can be separated by chemical means.

Hence, we an conclude that the atoms can only combine in fixed ratios, and they can only be separated by a chemical change, correctly describes a compound.

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Two elements are studied. One has atomic number X and one has atomic number X+2. It is known that element X is a halogen. To wha

vladimir2022 [97]

Answer:

Group 1 (or IA)

Explanation:

If element X is a halogen, then it belongs to the group 17 (or VIIA, under a different notation).

For each extra unit of atomic number, the group number increases by 1. That means that the X+1 element would belong to the group 18 (or VIIIA). <em>The X+2 element would thus belong in the group 1 </em>(or IA) one period higher (higher as in numeric value, not as in position in the periodic table).

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2 years ago

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Answer: B

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2 years ago

5. Given the cell notation Cu(s)|Cu2+(aq)||Ag+(aq)|Ag(s), what is the half-reaction that occurs at the anode?

Nataly_w [17]

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2 years ago

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Lead (ll) nitride+ammonium sulfate > lead(ll) sulfate + ammonium nitride

Alenkinab [10]

Answer:

$Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N$

Explanation:

Let's rewrite the given word equation in its chemical balanced equation representation:

1. Lead(II) nitride is represented by lead, Pb, in an oxidation state of 2+, while nitride is a typical nitrogen anion with a state 3-. As a result, the lowest common multiple between 2 and 3 is 6, meaning 2 lead cations are needed to balance 3 nitrogen anions: $Pb_3N_2$ .

2. Ammonium sulfate consists of an ammonium cation with a 1+ charge and sulfate anion with a 2- charge, two ammonium cations needed: $(NH_4)_2SO_4$ .

3. Lead(II) sulfate would have one lead cation and one sulfate anion, as they have the same magnitude of charges with opposite signs: $PbSO_4$ .

4. Ammonium nitride would require three amonium cations to balance the nitride anion: $(NH_4)_3N$ .

Let's write the balanced equation:

$Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N$

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3 years ago

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Dmitry [639]

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3 years ago

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