Answer:
75L of additional water to have a pH 1 solution
Explanation:
The reaction of HCl With NaOH is:
HCl + NaOH → H₂O + NaCl
By using molar mass of each reactant you can know how many moles will react, thus:
HCl: 364.6g HCl ₓ (1mol / 36.46g) = 10 moles HCl
NaOH: 80g NaOH ₓ (1mol / 40g) = 2 moles NaOH
That means after the reaction will remain in solution, 10-2 = 8 moles of HCl = 8 moles of H⁺ (In water, HCl dissociates as H⁺ and Cl⁻ ions).
A solution with pH = 1 contains:
pH = -log [H⁺]
1 = -log [H⁺]
0.1M = [H⁺]
As molarity, M is the ratio between moles and liters and you want a solution 0.1M having 8 moles of H⁺ you require:
0.1M = 8 moles H⁺ / 80L
As the student combines the solution with 5L of water, you require
<h3>75L of additional water to have a pH 1 solution</h3>
Solubility at 100 °C = 480 g / 100 mL of solution =: saturated solution
The proportion 240 g / 50 mL is equal to the saturated ratio 480 g / 100 mL
Then, 240 g of sugar in 50 mL of boiling water will make a saturated solution.
Answer: saturated
To answer this problem, we use Hess' Law to calculate the overall enthalpy of the reactions. The goal is to add all the reactions such that the final reaction is C<span>5H12 (g) + 8O2 (g) → 5CO2 (g) + 6H2O (l) through cancellation adn multiplication. The first equation is multiplied by 5, the second one is multiplied by 6 and the third one is reversed. The final answer is -3538 J or -3.54 x10^3 kJ.</span>
The five main branches of chemistry are organic chemistry, inorganic chemistry, analytical chemistry, physical chemistry and biochemistry. Chemistry can be further divided into many sub-branches that may fall under more than one of the main branches.
Answer:
<u>first step </u>
NO2(g) ------------------------------------> NO(g) + O(g)
<u>second step</u>
NO2(g) + O(g) -----------------------------> NO(g) + O2(g)
Explanation:
<u>first step </u>
NO2(g) ------------------------------------> NO(g) + O(g)
<u>second step</u>
NO2(g) + O(g) -----------------------------> NO(g) + O2(g)
