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stich3 [128]
3 years ago
13

A car starts at 25 m/s and then slows down at 13 m/s in 5 seconds. What is the acceleration of the car? What does the accelerati

on indicate?
Physics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

a=2.4m/s^2

Explanation:

Use V=vi+at

So, 13=25+a5

13-25=a5

\frac{-12}{5}=a

a=2.4m/s^2

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The intensity at distance from a spherically symmetric sound source is 100 W/m2. What is the intensity at five times this distan
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To solve this problem it is necessary to apply the concepts related to intensity as a function of power and area.

Intensity is defined to be the power per unit area carried by a wave. Power is the rate at which energy is transferred by the wave. In equation form, intensity I is

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The area of a sphere is given by

A = 4\pi r^2

So replacing we have to

I = \frac{P}{4\pi r^2}

Since the question tells us to find the proportion when

r_1 = 5r_2 \rightarrow \frac{r_2}{r_1} = \frac{1}{5}

So considering the two intensities we have to

I_1 = \frac{P_1}{4\pi r_1^2}

I_2 = \frac{P_2}{4\pi r_2^2}

The ratio between the two intensities would be

\frac{I_1}{I_2} = \frac{ \frac{P_1}{4\pi r_1^2}}{\frac{P_2}{4\pi r_2^2}}

The power does not change therefore it remains constant, which allows summarizing the expression to

\frac{I_1}{I_2}=(\frac{r_2}{r_1})^2

Re-arrange to find I_2

I_2 = I_1 (\frac{r_1}{r_2})^2

I_2 = 100*(\frac{1}{5})^2

I_2 = 4W/m^2

Therefore the intensity at five times this distance from the source is 4W/m^2

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Answer:

The current in the primary is 0.026 A

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