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Sedbober [7]
2 years ago
9

A group of students are planning to bake a cake on Saturday. Each member will bring flour. Aida will being 1/2 kilo and Fe will

bring 1/8 kilo and Lorna will bring 1/4 kilo. How many kilos of flour will they bring in all?
1: What is given?
2: What operation u use?
3:Number sentence
4: What is solution and answer?

Am so sorry I weak at math can yu answer for me​
Mathematics
1 answer:
I am Lyosha [343]2 years ago
6 0

Answer:

7/8 kilos

Step-by-step explanation:

Amount Aida brought = 1/2 kilo

Amount Fe brought= 1/8 kilo

Amount Lorna brought= 1/4 kilo

Amount they brought in all will be gotten by adding the individual amunts.

1/2 +1/8+ 1/4

The LCM of the denominators is 8

(4+1+2)/8

7/8 kilos of flour

I hope this is of help to you!!!

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In a kite ABCD, AB=AD, BC=CD; CAD=40° and
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Answer: See below

Step-by-step explanation:

From the figure attached below,

We know that by the SSS property, the two triangles are congruent

$$Since,$$\begin{aligned}&A D=A B(\text {Given}) \\&C D=B C(\text {Given}) \\&A C=A C \text { (Common side})\end{aligned}$$Hence,$$\triangle A B C \cong \triangle A C D$$By the properties of congruence,$$\angle O A D=\angle O A B=40^{\circ}$$$$\angle B=\angle D$$

Using the property of congruence to find the measure of all these angles:

Therefore, the measure of the angles are:

&a) \ B\widehat{ A} C=40^{\circ} \\ b) \ &B\widehat{C}A=180^{\circ}-\left(90^{\circ}+60^{\circ}\right)=30^{\circ} \\c) \ &A \widehat{D} C=60^{\circ}+50^{\circ}=110^{\circ}

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List the key words in the equation twice the sum of a number and three is seven and than write the equation
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The amount of energy it takes to lift a box might be a function of which of the following?
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Researchers studying the effect of diet on growth would like to know if a vegetarian diet affects the height of a child. Twelve
Eva8 [605]

Answer:

a)  t_{0.035},11=\pm2.201

b)  t=-2.963

c)  Reject\ H_0\ when\ \alpha=0.05

d)   t

   -2.963

Step-by-step explanation:

From the question we are told that:

Sample size n=12

Mean \=x=42.5

Standard deviation \sigma=3.8

Population mean \mu=45.75

Significance \alpha=0.05

 

Generally the hypothesis given by

H_0;\mu=45.75\\H_1:\neq =45.75

Generally the equation for test statistics is mathematically given by

t=\frac{\=x-\mu}{\sigma/\sqrt{n} }

t=\frac{42.5-45.75}{3.8/\sqrt{12} }

t=-2.963

Generally the Critical value is mathematically given by

t_{\alpha/2},d_t

\alpha=0.05 \\\alpha/2=0.025\\d_t=n-1=11

t_{0.035},11

From table

t_{0.035},11=\pm2.201

Therefore

t

-2.963

Reject\ H_0\ when\ \alpha=0.05

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