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garri49 [273]
2 years ago
8

What weight of sodium hydroxide will react with 73 gram of hydrogen chloride gas at NTP to Produce 117.0 gram of Nacl and 36 gra

m of water ?​
Chemistry
2 answers:
Wewaii [24]2 years ago
8 0

Let's write the equation

\\ \sf\longmapsto {NaOH\atop ?}+{HCl\atop 73g}\longrightarrow {NaCl\atop 117g}+{H_2O\atop 36g}

According to law of conservation of mass .

  • Mass of products=Mass of reactants

Let required value be x

\\ \sf\longmapsto x+73=117+36

\\ \sf\longmapsto x+73=153

\\ \sf\longmapsto x=153-73

\\ \sf\longmapsto x=80g

Marizza181 [45]2 years ago
4 0

Answer:

Equation:

NaOH + HCL = NaCl + H2O.

? 73g 117g 36g

Let the required value be x.

x + 73 = 117 + 36

x + 73 = 153

x = 153 - 73

x = 80.

hope \: helpfull.

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When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

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150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

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When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

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