Question

What weight of sodium hydroxide will react with 73 gram of hydrogen chloride gas at NTP to Produce 117.0 gram of Nacl and 36 gram of water ?​

Answer 1

Let's write the equation

$\\ \sf\longmapsto {NaOH\atop ?}+{HCl\atop 73g}\longrightarrow {NaCl\atop 117g}+{H_2O\atop 36g}$

According to law of conservation of mass .

• Mass of products=Mass of reactants

Let required value be x

$\\ \sf\longmapsto x+73=117+36$

$\\ \sf\longmapsto x+73=153$

$\\ \sf\longmapsto x=153-73$

$\\ \sf\longmapsto x=80g$

Answer 2

Answer:

Equation:

NaOH + HCL = NaCl + H2O.

? 73g 117g 36g

Let the required value be x.

x + 73 = 117 + 36

x + 73 = 153

x = 153 - 73

x = 80.

$hope \: helpfull.$