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3 months ago

the carbon canisters are about the size of a 55-gallon drum, how often would replacement be required?

1 answer:

Taya2010 [7]3 months ago

6 0

Drums made of carbon steel have proven to be a reliable and powerful container for storage and transportation. They are available in open and tight head configurations, sizes ranging from 5-110 gallons, and the workhorse 55 Gallon Drum.

<h3>What is about 55 Gallon Drum?</h3>

Drums made of carbon steel have proven to be a reliable and powerful container for storage and transportation. They are available in open and tight head configurations, sizes ranging from 5-110 gallons, and the workhorse 55 Gallon Drum.
They are suitable for packing a range of goods, including hazardous compounds. All carbon steel drums are made of carbon steel that meets ASTM standards.
The 42 carbon steel barrels that conform to industry standards are given below. They are extremely durable, thicker, heavier, and stronger than what industry standards call for. Any of our carbon steel drum designs are completely customizable by our in-house engineering department. To meet your specific needs and size requirements, ask about carbon steel drums that are specially built.

To learn more about 55 Gallon Drum refer to:

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The diameter of a biscuit is approximately 51 millimeters (mm). An atom of bismuth (Bi) is approximately 320. picometers (pm) in

astraxan [27]

Answer:

1.5e+8 atoms of Bismuth.

Explanation:

We need to calculate the <em>ratio</em> of the diameter of a biscuit respect to the diameter of the atom of bismuth (Bi):

$\\ \frac{diameter\;biscuit}{diameter\;atom(Bi)}$

For this, it is necessary to know the values in meters for any of these diameters:

$\\ 1m = 10^{3}mm = 1e+3mm$

$\\ 1m = 10^{12}pm = 1e+12pm$

Having all this information, we can proceed to calculate the diameters for the biscuit and the atom in meters.

<h3>Diameter of an atom of Bismuth(Bi) in meters</h3>

1 atom of Bismuth = 320pm in diameter.

$\\ 320pm*\frac{1m}{10^{12}pm} = 3.20*10^{-10}m$

<h3>Diameter of a biscuit in meters</h3>

$\\ 51mm*\frac{1}{10^{3}mm} = 51*10^{-3}m = 5.1*10^{-2}m$

<h3>Resulting Ratio</h3>

How many times is the diameter of an atom of Bismuth contained in the diameter of the biscuit? The answer is the ratio described above, that is, the ratio of the diameter of the biscuit respect to the diameter of the atom of Bismuth:

$\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1*10^{-2}m}{3.20*10^{-10}m}$

$\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1}{3.20}\frac{10^{-2}}{10^{-10}}\frac{m}{m}$

$\\ Ratio_{\frac{biscuit}{atom}}= 1.5*10^{-2+10}$

$\\ Ratio_{\frac{biscuit}{atom}}= 1.5*10^{8}=1.5e+8$

In other words, there are 1.5e+8 diameters of atoms of Bismuth in the diameter of the biscuit in question or simply, it is needed to put 1.5e+8 atoms of Bismuth to span the diameter of a biscuit in a line.

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2 years ago

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zvonat [6]

Answer: All of these answers are sorrect

ExplanationA scientist does all of these things while operforming a experiment

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How does water affect the growth of a plant?

irina1246 [14]

Answer:

Water transports important nutrients throughout the plant.

Explanation:

Much like blood in an animal, water is necessary for a plants survival, as it transports important nutrients from the soil all through the plant's stems and leaves.

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Tell uses of nitrogen

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Answer:

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Preservation of Food. Nitrogen gas is used to help with food preservation by preventing oxidative damage leading to food spoiling.
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Explanation:

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