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Ganezh [65]
3 years ago
10

(2a+b)/ b if a=-3, b=-2 1:4 2:-4 3:7 4:3.5

Mathematics
1 answer:
Ksivusya [100]3 years ago
3 0

Answer:

4

Step-by-step explanation:

2(-3)=-6

(-6+(-2))/-2

(-6-2)/-2

-8/-2

4

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Can someone please help me with this question
masya89 [10]

Answer:

I’d say C

Step-by-step explanation:

You should divide 112340 by 125. Then multiply it by 157. The result will be the closest to C.

5 0
3 years ago
Find an equation for the line below.<br><br><br> will give brainiest
pogonyaev

Answer: y=-\frac{x}{2}-6.5

Step-by-step explanation:

First find slope m. From observing the equation we can see that there are two points on the line. They are (-5,-4) and (-1,-6). Using the formula to find slope rise/run we get m = -0.5.

Now we use the point-slope formula to start the switch to the slope-intercept formula. Using (-1,-6) as our x and y values and switching m=-0.5 we get y + 6 = -0.5 ( x + 1). Simplify and we get y + 6 = -x/2 - -0.5. Subtract 6 from both sides and the final equation is y = -x/2 - 6.5.

8 0
3 years ago
Solve the system.
Alex777 [14]

Answer:

{x,y,z} = {-18,4,2}

Step-by-step explanation:

Solve equation [2] for the variable  x  

x = -10y + 2z + 18

Plug this in for variable  x  in equation [1]

(-10y+2z+18) + 9y + z = 20

- y + 3z = 2

Plug this in for variable  x  in equation [3]

 3•(-10y+2z+18) + 27y + 2z = 58

   - 3y + 8z = 4

Solve equation [1] for the variable  y  

 y = 3z - 2

Plug this in for variable  y  in equation [3]

  - 3•(3z-2) + 8z = 4

   - z = -2

Solve equation [3] for the variable  z  

 z = 2

By now we know this much :

 x = -10y+2z+18

   y = 3z-2

   z = 2

Use the  z  value to solve for  y  

 y = 3(2)-2 = 4

Use the  y  and  z  values to solve for  x  

 x = -10(4)+2(2)+18 = -18

6 0
3 years ago
Find the smallest value of p, such that 36p is a perfect cube.
insens350 [35]

Answer:

<h2>6 is the required answer.....</h2>
7 0
3 years ago
The sum of any two consecutive prime numbers is also prime
jek_recluse [69]
Let's consider two prime numbers where each is larger than 2

Say the primes 7 and 11. Adding them gets us 7+11 = 18. This counter example disproves the initial claim since 18 = 9*2 = 6*3 making 18 composite (not prime)

In general, if we let p and q be two primes such that q > p > 2 and q is the next prime after p, then p and q are both odd. If any of them were even then they wouldn't be prime (2 would be a factor)

Adding any two odd numbers together leads to an even number

Proof:
p = 2k+1 where k is some integer
q = 2m+1 where m is some integer
p+q = 2k+1+2m+1 = 2(k+m) + 2 = 2(k+m+1) which is in the form of an even number

That proof above shows us that adding any prime larger than 2 to its next prime up leads to an even number. This further shows us that the claim is false overall. It is only true if you restrict yourself to the primes 2 and 3, which add to 5. Otherwise, the claim is false. 
3 0
4 years ago
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