13.2962963 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer: The solution is the ordered pair (1/2, -3/4) so x = 1/2 and y = -3/4 pair up together. The two lines, when graphed, cross at this location.
note: 1/2 = 0.5 and -3/4 = -0.75; so the intersection point can be written as (0.5, -0.75)
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Explanation:
The second equation has y isolated. We can replace the y in the first equation with the expression 1/2x - 1
3x + 2y = 0
3x + 2( y ) = 0
3x + 2( 1/2x - 1) = 0 ... y is replaced with 1/2x-1
3x + 2(1/2x) + 2(-1) = 0 .... distribute
3x + x - 2 = 0 .... note how 2 times 1/2 is 1
4x - 2 = 0
4x = 2
x = 2/4
x = 1/2
Use this x value to find the y value it pairs with
y = (1/2)*x - 1
y = (1/2)*(1/2) - 1 ... replace x with 1/2
y = 1/4 - 1
y = 1/4 - 4/4
y = (1-4)/4
y = -3/4
Answer:
The calculated χ² = 0.57 does not fall in the critical region χ² ≥ 12.59 so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.
Step-by-step explanation:
1) We set up our null and alternative hypothesis as
H0: proportion of fatal bicycle accidents in 2015 was the same for all days of the week
against the claim
Ha: proportion of fatal bicycle accidents in 2015 was not the same for all days of the week
2) the significance level alpha is set at 0.05
3) the test statistic under H0 is
χ²= ∑ (ni - npi)²/ npi
which has an approximate chi square distribution with ( n-1)=7-1= 6 d.f
4) The critical region is χ² ≥ χ² (0.05)6 = 12.59
5) Calculations:
χ²= ∑ (16- 14.28)²/14.28 + (12- 14.28)²/14.28 + (12- 14.28)²/14.28 + (13- 14.28)²/14.28 + (14- 14.28)²/14.28 + (15- 14.28)²/14.28 + (18- 14.28)²/14.28
χ²= 1/14.28 [ 2.938+ 5.1984 +5.1984+1.6384+0.0784 +1.6384+13.84]
χ²= 1/14.28[8.1364]
χ²= 0.569= 0.57
6) Conclusion:
The calculated χ² = 0.57 does not fall in the critical region χ² ≥ 12.59 so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.
b.<u> It is r</u>easonable to conclude that the proportion of fatal bicycle accidents in 2015 was the same for all days of the week
