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lions [1.4K]
3 years ago
9

If a person pulls a cart to the right at 5N of force and another person pulls to the left with a 15N of force? What is the net f

orce and it what direction
Physics
1 answer:
zepelin [54]3 years ago
7 0

Answer:

The net force is 10 [N] acting to the left

Explanation:

To solve this type of problem we must make a sum of the forces acting on the cart, since the forces are vectors, we know that vectors can be added, In this way forces that go in the same direction are added and forces in opposite directions are subtracted.

FL = force to the left = - 15 [N]

FR = force to the right = 5 [N]

FT = Resultant force [N]

- 15 + 5 = FT

FT = - 10 [N]

The negative sign tells us that the force acts to the left.

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The distance between a speaker and a listener is 8.0 m. Determine the frequency of the sound wave if exactly 20 waves are formed
dmitriy555 [2]

The frequency of the wave is 6800 Hz

<u>Explanation:</u>

Given:

Wave number, n = 20

Speed of light, v = 340 m/s

Frequency, f = ?

we know:

wave number = \frac{frequency}{speed of light}

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3 years ago
The mass luminosity relation L  M 3.5 describes the mathematical relationship between luminosity and mass for main sequence sta
ivanzaharov [21]

Answer:

(a) <u>11.3 L</u>

(b) <u>10 M</u>

Explanation:

The mass-luminosity relationship states that:

Luminosity ∝ Mass^3.5

Luminosity = (Constant)(Mass)^3.5

So, in order to find the values of luminosity or mass of different stars, we take the luminosity or mass of sun as reference. Therefore, write the equation for a star and Sun, and divide them to get:

Luminosity of a star/L = (Mass of Star/M)^3.5 ______ eqn(1)

where,

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M = mass of Sun

(a)

It is given that:

Mass of Star = 2M

Therefore, eqn (1) implies that:

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Luminosity of Star = (2)^3.5 L

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(b)

It is given that:

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Therefore, eqn (1) implies that:

3160L/L = (Mass of Star/M)^3.5

taking ln on both sides:

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8.0583/3.5 = ln(Mass of Star/M)

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4 years ago
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Answer:

See Explanation

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When air is gradually removed from the jar by the pump, the sound intensity from the bell gradually decreases owing to the fact that air which is the medium through which sound waves are propagated is gradually being removed from the jar.

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