Answer:
ΔT = 78.32 °C
Explanation:
Kinetic energy of bullet is K
K = mv²/2
= .004 * ( 200 m/s )²/2
= 80 J
Half of the heat E = 40 J
Now a per the equation of energy transferred ,
E = cm ΔT
c is the specific heat of latent, m is the mass and ΔT is the change in temperature.
ΔT = 40 / ( .0305 × 4186 × .004)
ΔT = 78.32 °C
I would think 2.759kmockinbirds if you consider mockingbirds equal to a metre and kmockinbird to kilometres
Explanation:
1. Distance, d = 5 m
Time, t = 10 s
Speed = distance/time

2. Mass, m = 10 kg
Acceleration, a = 3 m/s³
Force, F = mass (m) × acceleration (a)
F = 10 × 3
= 20 N
3. Mass, m = 7 kg
Height, h = 4 m
Potential energy, E = mgh
E = 7 × 9.8 × 4
E = 274.4 J
Hence, this is the required solution.
Answer: The answer is D: 300,000km/s
Explanation: