Answer:
r=2.6 cm
Explanation:
Hi!
Lets call steel material 1, and the new alloy material 2. You know their densities:
The volume of a sphere with radius r is given by:
Then the masses of the bearings are:
For the masses to be the same:
![\rho_1 V_1 = \rho_2 V_2\\\frac{V_2}{V_1} =\frac{\rho_1}{\rho_2}\\(\frac{r_2}{r_1})^3 = \frac{8.08}{3.14}=2.57\\r_2=\sqrt[3]{2.57}\;r1 =1.37r_1=1.37*1.9cm=2.6cm](https://tex.z-dn.net/?f=%5Crho_1%20V_1%20%3D%20%5Crho_2%20V_2%5C%5C%5Cfrac%7BV_2%7D%7BV_1%7D%20%3D%5Cfrac%7B%5Crho_1%7D%7B%5Crho_2%7D%5C%5C%28%5Cfrac%7Br_2%7D%7Br_1%7D%29%5E3%20%3D%20%5Cfrac%7B8.08%7D%7B3.14%7D%3D2.57%5C%5Cr_2%3D%5Csqrt%5B3%5D%7B2.57%7D%5C%3Br1%20%3D1.37r_1%3D1.37%2A1.9cm%3D2.6cm)
<span>The equivalent resistance of a series circuit compared to the resistance values of the individual resistances in the circuit has a higher value. The equivalent resistance of a series circuit is calculated as the sum of all the individual resistances which gives it a larger value that the individual. Hope this helps.</span>
Answer:
initially- with positive potential differences - the current is directly proportional to the p.d. However, as the current through the filament increases, the heating effect caused in the lamp also increases and so the temperature of the filament rises. This increase in the filament's temperature also increases the resistance of the filament. As a result the rate of increase of the current decreases and a greater change in the potential difference is required to cause a change in the current. This can be seen on the curve as the gradient becomes more shallow (greater resistance). This same pattern is repeated when a negative potential difference is applied across the filament
the purpose of this experiment was to conduct to see the growth of pea plants with and without sun light
Answer:
Q = 41800[J]
Explanation:
These types of problems can be solved using the following heat transfer equation for quarps that increase or decrease their temperature as a function of mass.
where:
Q = Heat absorbed [J]
m = mass = 2 [kg]
DT = temperature change = 5 [°C]
Cp = specific heat of the water = 4180 [J/kg*°C]
![Q=2*4180*5\\Q=41800[J]](https://tex.z-dn.net/?f=Q%3D2%2A4180%2A5%5C%5CQ%3D41800%5BJ%5D)
Units of energy (Joules) [J]
