Ab=10
a^2+b^2=30
((a+b)^2=a^2+2ab+b^2=a^2+b^2+2*10=30+20=50
For
|a|=b, solve for
a=b and a=-b
so
|a-4|=3a-6
solve
a-4=3a-6 and a-4=-(3a-6)
first one
a-4=3a-6
minus a from both sides
-4=2a-6
add 6 to both sides
2=2a
divide by 2
1=a
other
a-4=-(3a-6)
a-4=-3a+6
add 3a both sides
4a-4=6
add 4 to both sides
4a=10
divide by 4
a=10/4
a=5/2
a=5/2 and 1
Answer:
400
Step-by-step explanation:
Car A costs 80d + 0.25m, where d is days and m is miles. Car B costs 100d + 0.10m. If you plug in 3 for d and make the equations equal, you get 240 + 0.25m = 300 + 0.10m. Combining like terms gives you 0.15m = 60, and dividing gives you m = 400.
It would be (-5, 15) or b.
