An object is dropped from a platform 100 feet high. Ignoring wind resistance, what will its speed be when it reaches the ground?
2 answers:
<span>if we assume the origin is at the dropping point and the object is merely dropped and not thrown up or down then y0 = 0 and v0 = 0. The equation reduces to </span> <span>y = 0 + 0t + ½gt² </span> <span>y = ½gt² </span> <span>t = √(2y/g) </span> <span>in the ft - lb - s system </span> <span>y = -100 ft </span> <span>g = -32.2 ft / s² </span> <span>t = √(2y/g) </span> <span>t = √(2(-100) / (-32.2)) </span> <span>t = 2.5 s</span>
the answer to the question is 2.5
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