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Blizzard [7]
4 years ago
10

What conditions are required for resonance to occur?

Physics
2 answers:
Citrus2011 [14]4 years ago
7 0

Answer:

B: a wave with the same amplitude as the object's natural frequency

Explanation:

took the test

CaHeK987 [17]4 years ago
3 0
B: A Wave with the same natural wavelength as an object's frequency
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All of the following measure mass except
mixer [17]
A centimeter cannot measure mass because mass is measured by grams. 

Answer: Centimeter 
5 0
3 years ago
Read 2 more answers
Use ideas of electromagnetic induction to explain how the input voltage is transformed into an output voltage
devlian [24]

With the help of a transformer  input voltage is transformed into an output voltage

​

<h3>What is induced voltage?</h3>

Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.

In this case, a magnet is pushed in and out of a wire coil attached to a high-resistance voltmeter.

Typically, a transformer's primary winding is attached to the input voltage source and changes electrical power into a magnetic field.

The secondary winding's role is to turn this alternating magnetic field into electricity, generating the necessary output voltage.

Hence with the help of a transformer input voltage is transformed into an output voltage.

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To learn more about the induced voltage refer to the link;

brainly.com/question/19482771

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5 0
2 years ago
Which of the following mixture can be separate using decantation method?​
vivado [14]

Answer:

Hi sorry for answering here but you didnt put the options there

Explanation:

I'll still try to answer though so maybe the mixture from one of the questions might be something like oil and water which don't mix and can be separated by decantation so something similar would work. Hope this helps

3 0
3 years ago
Assume that the electric field E is equal to zero at a given point. Does it mean that the electric potential V must also be equa
lyudmila [28]

Answer:

  • No, this doesn't mean the electric potential equals zero.

Explanation:

In electrostatics, the electric field \vec{E} is related to the gradient of the electric potential V with :

\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r})

This means that for constant electric potential the electric field must be zero:

V(\vec{r}) = k

\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r}) = - \vec{\nabla} k

\vec{E} (\vec{r}) = -  (\frac{\partial}{\partial x} , \frac{\partial}{\partial y } , \frac{\partial}{\partial z}) k

\vec{E} (\vec{r}) = -  (\frac{\partial k}{\partial x} , \frac{\partial k}{\partial y } , \frac{\partial k}{\partial z})

\vec{E} (\vec{r}) = -  (0,0,0)

This is not the only case in which we would find an zero electric field, as, any scalar field with gradient zero will give an zero electric field. For example:

V(\vec{r})= (x+2)^2 (y+4)^3 (z+5)^4

give an electric field of zero at point (0,0,0)

8 0
3 years ago
What is the relationship between the temperature of a star and its luminosity?
Sladkaya [172]
The Luminosity of a star is proportional to its Effective Temperature to the 4th power and its Radius squared.
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3 years ago
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