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3 years ago

What is conclusion about potential difference (voltmeter readings) in a parallel electric circuit ?

Physics

1 answer:

Ainat [17]3 years ago

5 0

Answer: the conclusion is that

Explanation:

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A 28 g bullet pierces a sand bag 29 cm thick. If the initial bullet velocity was 55 m/s and it emerged from the sandbag with 18

Bumek [7]

The correct answer to the question is 130.4 N.

CALCULATION;

The mass of the bullet is given as m = 28 gram = 0. 028 kg.

The initial velocity of the bullet u = 55 m/s

The final velocity of the bullet v = 18 m/s.

The distance covered by the bullet through the sand bag s = 29 cm.

= 0.29 m

Let the acceleration of the bullet is a .

From equation of kinematics, we know that-

$v^2-u^2=\ 2as$

⇒ $a=\ \frac{v^2-u^2}{2s}$

$=\ \frac{(18)^2-(55)^2}{2\times 0.29}\ m/s^2$

$=\ -4656.897\ m/s^2$

The negative sign is used due to the fact that force is opposing in nature. Its velocity is decreasing with time.

From Newton's second law of motion, we know that net force on a body is equal to the product of mass with acceleration.

Mathematically F = ma.

Hence, the frictional force exerted on the bullet is calculated as -

F = m × a

= 0.028 × (-4656.897) N

= -130.4 N [ANS]

Here, N ( newton) stands for the unit of force.

8 0

3 years ago

If two bodies weighing 10 kg and 20 kg respectively are standing at the

kvv77 [185]

Answer:

potential energy = mgh , where m is mass of body , g is acceleration due to gravity and h is given height

since both of the body are at same height above the ground , so the body having greater mass will have more potential energy

that is 20 kg body will have higher P.E

Explanation:

7 0

3 years ago

Assume this field is generated by a point charge of Q = 5 × 10-9 C. How far away is this charge located? Give your answer in met

marshall27 [118]

E=Eq,

where F is the electrostatic force (or Coulomb force) exerted on a positive test charge q.

7 0

3 years ago

Will a vector at 45 degrees to the horizontal be larger or smaller than its horizontal and vertical components? By how much?

never [62]

Larger. How big depends on the size of the vector. But think about pythagoras theorem to solve for the vector.

8 0

3 years ago

If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude

Mrrafil [7]

The magnitude of the electric field at this location is $1.5\times 10^{10} N/C$

<u>Explanation:</u>

Given

$Charge\ of\ the\ particle\ Q=4.3\times 10^-18\ C\\Force\ with\ which\ it\ is\ attracted\ F=6.5\times 10^-8\ N$

Electric field at this location determined by the force and charge.

E=F/Q

$E=\frac{6.5\times 10^-8}{4.3\times10^-18} =1.5\times\ 10^{10} \ N/C$

7 0

4 years ago