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jeyben [28]
3 years ago
5

PLEASE DO ASAP IM POSTING ONE MORE

Physics
2 answers:
tino4ka555 [31]3 years ago
8 0
Rain gauge measures rain shadow units mil
KIM [24]3 years ago
7 0

Answer rain gauge measures rain shadow units millimetres

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Склянка с воздухом закрыта «пробкой» из мыльной пены.
alexira [117]
Склянка с воздухом закрыта «пробкой» из мыльной пены.
Определи, что произойдёт, если склянку частично погрузить в ёмкость с горячей водой?

Выбери правильный вариант ответа.
Мыльная пена будет перемещаться внутрь склянки.
Мыльная пена будет подниматься наружу.

Что произойдёт с давлением воздуха внутри склянки?
Выбери правильный вариант ответа.
Давление не изменится.

и дальнейшее объяснение произошедшего

Может показаться, что воздух в вашей бутылке - просто пустое пространство, но на самом деле это смесь газов. Сила, с которой отдельные молекулы отскакивают от внутренней и внешней стороны бутылки, называется давлением.
5 0
3 years ago
In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of t
muminat
<h2><em><u>⇒</u></em>Answer:</h2>

In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of the legs from the crouch position is 0.600 m and the acceleration achieved from this position is 1.25 times the acceleration due to gravity, g . How far can they jump? State your assumptions. (Increased range can be achieved by swinging the arms in the direction of the jump.)

Step-by-Step Solution:

Solution 35PE

This question discusses about the increased range. So, we shall assume that the angle of jumping will be  as the horizontal range is maximum at this angle.

Step 1 of 3<

/p>

The legs have an extension of 0.600 m in the crouch position.

So,  m

The person is at rest initially, so the initial velocity will be zero.

The acceleration is  m/s2

Acceleration  m/s2

Let the final velocity be .

Step 2 of 3<

/p>

Substitute the above given values in the kinematic equation  ,

m/s

Therefore, the final velocity or jumping speed is  m/s

Explanation:

3 0
3 years ago
Read 2 more answers
Which of the following is the best definition of an isotope?
almond37 [142]
Option A looks like the best definition
4 0
3 years ago
Quick Quiz 40.2 While standing outdoors one evening, you are exposed to the following four types of electromagnetic radiation: y
Firlakuza [10]

The order of decreasing photon energy is FM radio, AM radio, yellow light, and microwaves.

Electromagnetic radiation: The electromagnetic field's waves, which are conveying electromagnetic radiant energy through space, are what make up electromagnetic radiation. It consists of X-rays, gamma rays, microwaves, infrared, light, and radio waves. These waves are all a component of the electromagnetic spectrum.

Microwave radiation has wavelengths between one meter and one millimeter, which correspond to frequencies between 300 MHz and 300 GHz, respectively.

Radio waves: The electromagnetic spectrum's longest wavelengths, which are found in radio waves, are normally found at frequencies of 300 gigahertz and below.

The radio waves have the highest photon energy and the lowest is microwaves.

So, the highest to lowest order is FM radio, AM radio, yellow light and microwaves.

Learn more about waves here:

brainly.com/question/1968356

#SPJ4

4 0
2 years ago
Assume that at sea-level the air pressure is 1.0 atm and the air density is 1.3 kg/m3.
scoundrel [369]

Answer

Pressure, P = 1 atm

air density, ρ = 1.3 kg/m³

a) height of the atmosphere when the density is constant

   Pressure at sea level = 1 atm = 101300 Pa

   we know

   P = ρ g h

   h = \dfrac{P}{\rho\ g}

   h = \dfrac{101300}{1.3\times 9.8}

          h = 7951.33 m

height of the atmosphere will be equal to 7951.33 m

b) when air density decreased linearly to zero.

  at x = 0  air density = 0

  at x= h   ρ_l = ρ_sl

 assuming density is zero at x - distance

 \rho_x = \dfrac{\rho_{sl}}{h}\times x

now, Pressure at depth x

dP = \rho_x g dx

dP = \dfrac{\rho_{sl}}{h}\times x g dx

integrating both side

P = g\dfrac{\rho_{sl}}{h}\times \int_0^h x dx

P =\dfrac{\rho_{sl}\times g h}{2}

 now,

h=\dfrac{2P}{\rho_{sl}\times g}

h=\dfrac{2\times 101300}{1.3\times 9.8}

  h = 15902.67 m

height of the atmosphere is equal to 15902.67 m.

6 0
3 years ago
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