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slamgirl [31]
3 years ago
15

(08.02 MC)

Chemistry
1 answer:
lesantik [10]3 years ago
3 0

Answer:

d. 0.208 M NaOH

Explanation:

M[NaOH] = 23+16+1= 40g/mol

2.40L = 2.4dm3

M=m/Mv

M=20.0g/40g/mol×2.4dm3

M=20.0g ÷ 96

M= 0.208 M NaOH

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Explanation:

300 ml x300mm Hg/500 mm Hg= 180 ml

pressure goes up volume goes down

P1V1 =P2V2

V2= V1 x P1/P2

4 0
4 years ago
Why do electrons transition between energy levels within the atom, and how do we detect these transitions?
Sedaia [141]

Answer:

See explanation

Explanation:

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3 years ago
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circulatory system

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3 0
3 years ago
Read 2 more answers
Explain what a polar bond is and how the electronegativities of the two atoms in the bond compare.
Art [367]

A  polar  bond is a bond where  there is an uneven distribution of charge in the molecule, due to the ability of more electronegative atoms to attract electron pairs towards themselves which creates an electric dipole. The more electronegative atom gets a partial positive charge and the less electronegative atom gets a partial positive charge.

For a bond between two atoms to be polar, the difference in electronegativity between the two atoms should be roughly between 0.5 and 2.0. In this case, the more electronegative atom will draw the charge density towards itself to create the dipole, but not strong enough to completely  strip the other atoms of electrons.  The bigger the difference in electronegativity, the more polar the bond.  


8 0
3 years ago
What mass of neon gas is required to fill a 5.00-L container to<br> a pressure of 1.02 atm at 25 °C?
sweet [91]

Answer:

m=4.21g

Explanation:

Hello,

In this case, by using the ideal gas equation:

PV=nRT

We can compute the mass of neon gas at the given conditions by firstly computing the moles and also considering the temperature in kelvins (298K):

n=\frac{PV}{RT}=\frac{1.02atm*5.00L}{0.082\frac{atm*L}{mol*K}*298K}\\  \\n=0.209mol

Finally, by using the atomic mass of neon gas (20.18g/mol) we compute the required mass to fill the 5.00-L container:

m=0.209mol*\frac{20.18g}{1mol}\\ \\m=4.21g

Best regards.

4 0
3 years ago
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