The balanced reaction is 2KClO3 --> 2KCl + 3O2
We first divide the 400.0 g KClO3 by the molar mass of 122.55 g/mol to get 3.26 mol KClO3. Next, we use the coefficients: 3.26 mol KClO3 * (3 mol O2 / 2 mol KClO3) = 4.896 mol O2. Multiplying this by the molar mass of 32 g/mol gives 156.67 g O2.
Percent yield = 115.0 g / 156.67 g = 0.734 = 73.40%
Answer:
It can be represented using the chemical formula P 20 5.It has a molecular weight of 141.945 grams per mole and its density is about 2.39 G/cm 3.It can also be termed as Diphosphorus Pentoxide, Phosphorus(V) Oxide,
Phosphoric Anhydride, Tetraphosphorus Decaoxide, Tetraphosphorus Decoxide.
Answer:
In the desert, the climate is hot and dry, while in the tundra, it is cold and wet.
Explanation:
in the desert, plants need more water, while in the tundra, they have ice and snow
I don’t have a picture but I can describe it to you.
The hydrogen that is attached at the tertiary position on the heptatriene (at the 7-methyl) would be very acidic, as removal would leave a positive charge that could be moved throughout the ring through resonance. This would mean that the three double bonds would be participating in resonance, and the deprotonated structure would be aromatic, thus making this favorable.
The hydrogen that is attached at the tertiary position on the pentadiene (5-methyl) would NOT be acidic, as removal would cause an antiaromatic structure.
Any other hydrogens would NOT be acidic. Those vinylic to their respective double bonds would seriously destabilize the double bond if removed, and hydrogens attached to the methyl group jutting off the ring have no incentive to leave the carbon.
Hope this helps!
