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Olin [163]
3 years ago
11

If two atoms are bonded with a bond energy of 87 kJ, what must be done to break the bond?

Chemistry
1 answer:
SSSSS [86.1K]3 years ago
7 0
I would say the energy has to be decreased by 87 kj because the bonding is held together by 87 kj so removing that should prevent the bonding from taking place or reverse it I believe. In other words, a certain amount of energy is required to hold the bond together and in the absence of that energy, the bonding will not take place.
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Write a balanced equation showing how this nucleus decays to form an α particle: thorium−230.
Ostrovityanka [42]
When   an  atomic  nucleus  emits  an  alpha  particle  it  decay  into  an atom   with atomic  number  2  less   and   mass number  4  less.  Thus  Thorium   230   decay    as  follows.

230 90Th  -------> 226  88Th  +  4 2 He

thorium  is  in  the  atomic  number   90  thus  it  during   alpha decay  it reduces  to  atomic  number  88  while  its  230   mass  number  reduces  to   226
6 0
3 years ago
Calculate the number of water (H2O) molecules produced from the decomposition of 75.50 grams of Iron (III) hydroxide (Fe(OH)3).
Phantasy [73]

Answer: 6.38\times 10^{23} molecules of water are produced.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Fe(OH)_3=\frac{75.50g}{106.8g/mol}=0.707moles

The balanced chemical reaction is:

2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O  

According to stoichiometry :

2 moles of Fe_2O_3 produce = 3 moles of H_2O

Thus 0.707 moles of Fe_2O_3 will produce=\frac{3}{2}\times 0.707=1.06moles  of H_2O  

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles.

Thus 1.06 moles of H_2O contains = \frac{6.023\times 10^{23}}{1}\times 1.06=6.38\times 10^{23} molecules

5 0
3 years ago
This element has 3 electrons in its Lewis dot structure and is in the 3p orbital section.
Lynna [10]
The answer is Al. If it is a main group element with 3 electrons in its Lewis dot structure, it must be in group 3A. If it is in the 3p orbital section, then it must be in period 3, since the p orbital is a valence orbital and the number that preceeds it is the principal quantum number. Therefore, your answer is the element in period 3 and group 3A, which is aluminum.
3 0
3 years ago
An(A)=25,n(B)=40,n(AuB)=50<br><br>AnB​
puteri [66]

Answer:

5879

Explanation:

3896_+746864uyrhufhj

5 0
3 years ago
Nitrogen dioxide is a red-brown gas responsible for the brown color of smog. A container of nitrogen dioxide that is at low pres
____ [38]

Answer:

Initially 1.51\times 10^{-2} moles of nitrogen dioxide were in the container .

Explanation:

Volume of the container at low pressure and at room temperature =V_1=3.4 L

Number of moles in the container = n_1

After more addition of nitrogen gas at the same pressure and temperature.

Volume of the container after addition = V_2=5.11 L

Number of moles in the container after addition=n_2=2.28\times 10^{-2} mol

Applying Avogadro's law:

\frac{Volume}{Moles}=constant (at constant pressure and temperature)

\frac{V_1}{n_1}=\frac{V_2}{n_2}

n_1=\frac{V_1\times n_2}{V_2}=\frac{3.4 L\times 2.28\times 10^{-2} mol}{5.11 L}

n_1=1.51\times 10^{-2} mol

Initially 1.51\times 10^{-2} moles of nitrogen dioxide were in the container .

8 0
3 years ago
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