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3 years ago

If A vector = i^-j^+k^ then unit vector in the direction of A vector

Physics

1 answer:

Novosadov [1.4K]3 years ago

6 0

If A = i - j + k, then the magnitude of A is

||A|| = √(1² + (-1)² + 1²) = √3

Then the unit vector in the direction of A is 1/||A|| multiplied by A :

u = A/||A|| = (i - j + k)/√3

(choice D)

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Joules constant, 4.1868 J/cal, is an equivalence relation for 4.1868 Joules of work for 1 calorie of heat delivered to a substan

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Answer:

The final answer is $6.1 BTU = 6.5621*103 KJ$

Explanation:

$1 BTU= 252 cal\\1 BTU =252 × 4.2 kJ\\6.1 BTU = 252 × 6.1×4.2 kJ = 6562.08 kJ\\ = 6.5621 × 103 kJ\\$

Hence, $6.1 BTU = 6.5621 × 103 kJ$

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3 years ago

A 25kg mass is suspended at the end of a horizontal, massless rope that extends from a wall on the left and from the end of a se

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<h2>Answer:20.97g N,32.63g N</h2>

Explanation:

We consider the forces at the knot.

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$T_{2}Sin(50^{0}})$ is the vertical component of tension $T_{2}$ at the knot.

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The horizontal forces are

$-T_{1}$ is the tension in the rope acting left.

$T_{2}Cos(50^{0})$ is the horizontal component of tension $T_{2}$ acting towards right.

Since the knot has no mass,it is always in equilibrium.

So,the sum of forces acting on it will be zero.

Balancing vertical forces gives,

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Balancing horizontal forces gives,

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$T_{1}=32.63g\times Cos(50^{0})=20.97gN$

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3 years ago

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The path difference is 0.2 millimeters.

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3 years ago

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wolverine [178]

Answer:

P = W / t = m g s / t = m g v where work by auto = m g s

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= m g v sin 8.75 = 1222 v Joules / sec

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3 years ago

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The answer is

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