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3 years ago

What is the period of a pendulum near Earth’s surface that is 130 cm long?

Physics

1 answer:

gulaghasi [49]3 years ago

4 0

Answer:

A). 2.3 s

Explanation:

Given that,

Length of the string = 130cm or 1.3 m

g near Earth's surface = 9.8 $ms^{-2}$

To determine the period of a pendulum near Earth’s surface;

T = 2 π $\sqrt{\frac{L}{g} }$

T = 2π $\sqrt{\frac{1.3}{9.8} }$

T = 2.3 sec

Therefore, the period of the pendulum near the earth's surface is 2.3 sec.

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The coil of wire in the center of the screen encompasses an area through which magnetic field lines pass, so there is a magnetic

fredd [130]

Answer:

<em>No, the coil will produce no flow of current or potential difference.</em>

Explanation:

Magnetic field flux is the number of magnetic field line passing through a given area. It depends on the area and the magnetic field strength through this area. For electromagnetic induction to occur, there must be a constantly changing magnetic field. This is according to Faraday's law of electromagnetic induction that states that the induced EMF is directly proportional to the rate of change in flux ΔФ/Δt, and is also proportional to the number of turns on the coil. A changing magnetic field will lead to a break in the flux linkage, which induces current or potential difference on the coil. A stationary coil through a magnetic filed will therefore produce no electric flow of current or potential difference on the coil.

6 0

4 years ago

Photons of what minimum frequency are required to remove electrons from gold? note: the work function for gold is 4.8 ev.

kolbaska11 [484]

In the photoelectric effect, the energy given by the incoming photon is used partially to extract the electron from the metal (work function) and the rest is converted into kinetic energy of the electron:
$hf= \phi + K$
where
hf is the energy of the photon, with h being the Planck constant and f the frequency of the photon
$\phi$ is the work function
K is the kinetic energy of the electron

When K=0, we have the minimum energy required to extract the electron from the metal, so the equation becomes
$hf= \phi$ (1)

If we convert the work function of gold into Joules:
$\phi=4.8 eV = 7.69 \cdot 10^{-19}J$
We can re-arrange eq.(1) to find the minimum energy of the photon:
$f= \frac{\phi}{h}= \frac{7.69 \cdot 10^{-19}J}{6.6 \cdot 10^{-34} Js} =1.17 \cdot 10^{15} Hz$

5 0

4 years ago

Describe the wavelength of a longitudinal wave.

Lilit [14]

In Longitudinal waves, particles of the medium vibrate around their mean positions. Their amplitude of vibration is in the direction of the propagation of the wave. In transverse wave of longitudinal wave, <em>the wavelength is always the distance between two particles which are in the same phase.</em>

If we take pressure waves, (sound waves), we have pressure variations created by sound wave along its path. Pressure is maximum at compression regions and pressure is minimum at rarefaction region. In between the two, pressure of air remains as the pressure when there is no wave.

<em>The wave length is then the distance between two consecutive rarefactions or two consecutive compression regions.</em>

<em>It is also the distance traveled by the wave in one time period.</em> Time period is the time the particles in the medium take to vibrate towards the end, turn back to reach the other end of their oscillation and then reach back their position.

6 0

3 years ago

A toy rocket launcher can project a toy rocket at a speed as high as 35.0 m/s.

Anestetic [448]

Answer:

(a) 62.5 m

(b) 7.14 s

Explanation:

initial speed, u = 35 m/s

g = 9.8 m/s^2

(a) Let the rocket raises upto height h and at maximum height the speed is zero.

Use third equation of motion

$v^{2}=u^{2}+2as$

$0^{2}=35^{2}- 2 \times 9.8 \times h$

h = 62.5 m

Thus, the rocket goes upto a height of 62.5 m.

(b) Let the rocket takes time t to reach to maximum height.

By use of first equation of motion

v = u + at

0 = 35 - 9.8 t

t = 3.57 s

The total time spent by the rocket in air = 2 t = 2 x 3.57 = 7.14 second.

8 0

3 years ago

Consider the baby being weighed in Figure 4.25.

Lunna [17]

The mass and tension due to the system are as follows:

The mass of the child and scale = 10.6 kg

The tension T, in the cord attaching the child to the scale = 104N

The tension T', in the cord attaching the scale to the ceiling T' = 108.9 N

<h3>What is tension?</h3>

Tension is a type of pulling force due transmitted by means of a string or cable.

<h3>Force = mass * acceleration due to gravity</h3>

a) The mass of the child and scale = 104/9.81 = 10.6 kg

b) The tension T, in the cord attaching the child to the scale = scale reading = 104N

c) The tension T', in the cord attaching the scale to the ceiling = scale reading + weight of scale

T' = 104 + (0.5 * 9.81)

T' = 108.9 N

d) The sketch is attached in the picture

In conclusion, the tension is force exerted on the cord due to the weight of the scale and the baby.

Learn more about tension force at: brainly.com/question/24994188

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4 0

2 years ago