Answer:
The correct answer is Option C (E1) and Option B (carbocation).
Explanation:
- Intramolecular immunity idols are considered as that of the formation mechanism with E1 responses or reactivity.
- Reactants with E1 were indeed obligations of both parties, meaning that an E1 reaction was conducted thru all the two stages known as ionization but rather deprotonation. Involves the absence of either an aromatic ring, a carbocation has been generated throughout the ionization solution.
Some other possibilities offered aren't relevant to the procedure outlined. So the above alternative is accurate.
Answer:
Mass = 8 g
Explanation:
Given data:
Mass of MgO formed = 20 g
Mass of oxygen needed = ?
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
Number of moles of MgO:
Number of moles = mass/molar mass
Number of moles = 20 g/ 40 g/mol
Number of moles = 0.5 mol
Now we will compare the moles of MgO and O₂ from balance chemical equation:
MgO : O₂
2 : 1
0.5 : 1/2×0.5 = 0.25 mol
Mass of oxygen required:
Mass = number of moles × molar mass
Molar mass of O₂ is 32 g/mol
Mass = 0.25 mol × 32 g/mol
Mass = 8 g
Answer:
There are often not more than one or two independent variables tested in an experiment.
When Q is equal the initial concentration of the products / the initial concentration of the reactants.
so, Q = [Ag]*[Cl-] and we neglected [AgCl] as it is solid
∴ Q = 10^-6 * 10^-5
= 10^-11
now we will compare the value of Q with the value of Keq:
when Q = Keq so, the system is in equilibrium
and when Q > Keq so, the reaction will go forward (shift to right) to achieve equilibrium.
and when Q< Keq so, the reaction will go left (shift to left) to achieve equilibrium.
when Q = 10^-11 and Keq = 10^20
∴Q< Keq
and the reaction will shift to left.
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