Answer:
v(t) = 2Ht - F
Explanation:
Since, the position of the object is given in terms of time (t) as follows:
x(t) = Ht² - Ft + G
where,
H, F, G are constants.
Therefore, the velocity of the object can also be found in terms of the time (t), by simply taking the derivative of the given position equation with respect to time. So, the velocity can be found as follows:
(d/dt) x(t) = (d/dt)(Ht² - Ft + G)
v(t) = (d/dt)(Ht²) - (d/dt)(Ft) + (d/dt)(G)
v(t) = H (d/dt)(t²) - F (d/dt)(t) + (d/dt)(G)
v(t) = H(2t) - F(1) + 0
<u>v(t) = 2Ht - F</u>
Answer:
Deceleration of the runner is -23.33
Given:
Initial velocity = 3.5
Final velocity = 0
Time = 0.15 s
To find:
Deceleration of runner = ?
Formula used:
According to first equation of motion,
v = u + at
Where, v = final velocity
u = initial velocity
a = deceleration
t = time
Solution:
According to first equation of motion,
v = u + at
Where, v = final velocity
u = initial velocity
a = deceleration
t = time
0 = 3.5 + a (0.15)
-3.5 = 0.15 (a)
a =
a = -23.33
Negative sign shows that it is deceleration.
Thus, deceleration of the runner is -23.33
I think the vehicle relation to the hearer is : Past the hearer
Have you ever walk when a motor cycle run past you ? You will notice that you will hear less sound as the motor cycle goes further
Hope this helps
Answer:
Since the car comes uniformly to a stop, the force that acts on the vehicle is the net force whose magnitude is equal to 1320 N.
Explanation:
The force acting on the vehicle is given:
Where:
m: is the mass = 1100 kg
a: is the acceleration = -1.2 m/s²
We can find the magnitude of the net force:
Since the car comes uniformly to a stop, the force that acts on the vehicle is the net force calculated above.
I hope it helps you!