Answer:
The electric current in the wire is 0.8 A
Explanation:
We solve this problem by applying the formula of the magnetic field generated at a distance by a long and straight conductor wire that carries electric current, as follows:
B= Magnetic field due to a straight and long wire that carries current
u= Free space permeability
I= Electrical current passing through the wire
a = Perpendicular distance from the wire to the point where the magnetic field is located
Magnetic Field Calculation
We cleared (I) of the formula (1):
Formula(2)
a =8cm=0.08m
We replace the known information in the formula (2)
I=0.8 A
Answer: The electric current in the wire is 0.8 A
Answer:
A) ΔU = 3.9 × 10^(10) J
B) v = 8420.75 m/s
Explanation:
We are given;
Potential Difference; V = 1.3 × 10^(9) V
Charge; Q = 30 C
A) Formula for change in energy of transferred charge is given as;
ΔU = QV
Plugging in the relevant values gives;
ΔU = 30 × 1.3 × 10^(9)
ΔU = 3.9 × 10^(10) J
B) We are told that this energy gotten above is used to accelerate a 1100 kg car from rest.
This means that the initial potential energy will be equal to the final kinetic energy since all the potential energy will be converted to kinetic energy.
Thus;
P.E = K.E
ΔU = ½mv²
Where v is final velocity.
Plugging in the relevant values;
3.9 × 10^(10) = ½ × 1100 × v²
v² = [7.8 × 10^(8)]/11
v² = 70909090.9090909
v = √70909090.9090909
v = 8420.75 m/s
Answer:
<em>the</em><em> </em><em>correct</em><em> </em><em>answer</em><em> </em><em>is</em>
Explanation:
<em>The</em><em> </em><em>small</em><em> </em><em>intestine</em><em> </em><em>absorbs</em><em> </em><em>most</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>nutrients</em><em> </em><em>in</em><em> </em><em>your</em><em> </em><em>food</em><em>,</em><em>an</em><em>d</em><em> </em><em>you</em><em>r</em><em> </em><em>circulatory</em><em> </em><em>system</em><em> </em><em>passes</em><em> </em><em>them</em><em> </em><em>on</em><em> </em><em>to</em><em> </em><em>other</em><em> </em><em>parts</em><em> </em><em>of</em><em> </em><em>your</em><em> </em><em>body</em><em> </em><em>to</em><em> </em><em>store</em><em> </em><em>or</em><em> </em><em>use.</em><em> </em><em>Special</em><em> </em><em>cell</em><em>s</em><em> </em><em>helped</em><em> </em><em>absorbed</em><em> </em><em>nutrients</em><em> </em><em>cross</em><em> </em><em>the</em><em> </em><em> </em><em>intestinal</em><em> </em><em>lining</em><em> </em><em> </em><em>into</em><em> </em><em>your</em><em> </em><em>blood</em><em> </em><em>stream</em><em>.</em>
<em><u>hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>works</u></em><em><u> </u></em><em><u>out</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em>
I believe the answer is radiation
Answer:
<em>The number 0.0217 has 3 significant digits</em>
Explanation:
<u>Significant Digits
</u>
These are digits that contribute to the significance of the number. Some rules apply to discard the non-significant digits like:
- Leading zeros
- Trailing zeros (with exceptions)
Our number is 0.0217 has two leading zeros before the 2 because they only occupy space to indicate the order of magnitude of the number. Only the 2,1,7 are significant digits, thus
The number 0.0217 has 3 significant digits
